Yes, if the number is less than '1'.
Just the opposite, if the number is greater than '1'.
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False. Only a square number greater than 1 is always bigger than its root. For example, the root of 16 is 4, but the root of 1/16 (0.0625) is 1/4 (0.25) and the square root of 1 is 1.
The width can be any number greater than zero and less than the square root of 35, and the length can be any number greater than the square root of 35, subject to the constraint that the product of the length and the width must be 35.
Any number greater than 0 has two square roots, a positive square root and a corresponding negative square root. Rounded to two decimal places, the square roots of 0.25 are ±0.5.0.5
The square root of 20 is approximately 4.47, while the square root of 10 is approximately 3.16. Therefore, the square root of 20 is greater than the square root of 10. This can be confirmed by squaring both values to see which results in a larger number.
4 squared is 16 The square root of 4 is 2 Hence, 4 squared is 14 greater than the square root of 4.
when the number is greater than 1
No there is not. If you are looking for prime factors of a number and you get to the square root of that number you can stop. Yes, there is. If an integer is not itself a prime, then one of its factors will be less or equal to its square root and the "co-factor" will be greater than or equal to the square root. But both cannot be greater than the square root so, when searching for factors, you can stop when you reach the square root.
Since the square root of a number is the "number times itself that equals the original number," it makes sense that the larger the original number, then the larger the square root. The value of the square root of 2 will be greater than the value of the square root of 1.5.
Yes, if the number is less than 1
the square root of 10
It is greater than the negative square root of 8, but smaller than the positive square root of 8.
No.
a square number is a number that you multiply the same number like:8.8 = 64 get it
3 is greater than the square root of 8.
38 is greater than the square root of 38
8 is greater than the square root of 60
when x is a negative number --- is a wrong answer since square root of a negative number is not defined. So x has to be zero or a positive number. The correct answer is that when x lies between 0 and 1 (with both limits excluded), its square root is greater than the number itself. Of course at both limits, the square root (assuming the positive square root - since a square root of a number can be positive or negative, both with the same absolute value) is the same as the number.