when the number is greater than 1
Since the square root of a number is the "number times itself that equals the original number," it makes sense that the larger the original number, then the larger the square root. The value of the square root of 2 will be greater than the value of the square root of 1.5.
the square root of 10
No.
3 is greater than the square root of 8.
Yes, if the number is less than '1'.Just the opposite, if the number is greater than '1'.
when the number is greater than 1
No there is not. If you are looking for prime factors of a number and you get to the square root of that number you can stop. Yes, there is. If an integer is not itself a prime, then one of its factors will be less or equal to its square root and the "co-factor" will be greater than or equal to the square root. But both cannot be greater than the square root so, when searching for factors, you can stop when you reach the square root.
Since the square root of a number is the "number times itself that equals the original number," it makes sense that the larger the original number, then the larger the square root. The value of the square root of 2 will be greater than the value of the square root of 1.5.
the square root of 10
It is greater than the negative square root of 8, but smaller than the positive square root of 8.
No.
a square number is a number that you multiply the same number like:8.8 = 64 get it
3 is greater than the square root of 8.
38 is greater than the square root of 38
8 is greater than the square root of 60
when x is a negative number --- is a wrong answer since square root of a negative number is not defined. So x has to be zero or a positive number. The correct answer is that when x lies between 0 and 1 (with both limits excluded), its square root is greater than the number itself. Of course at both limits, the square root (assuming the positive square root - since a square root of a number can be positive or negative, both with the same absolute value) is the same as the number.