There are three numbers between 10 and 50 which are divisible by both 3 and 5. All numbers that are multiples of 3 and 5 are the multiples of the lowest common multiples (lcm) of 3 and 5 which is 15. The multiples of 15 between 10 and 50 are {15, 30 and 45}, thus there are 3 numbers.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
Since all 3 are prime numbers LCM = 3 * 5 * 7 = 105 All multiples of 105 are multiples of 3, 5 and 7
If the numbers are multiples of 2, 3, and 5, they are multiples of 2 x 3 x 5 = 30. Here are some multiples of 30: 30, 60, 90, 120, 150, 180, 210, 240, 270, 300, ...
It is not possible it has to be an even number.Plus it has no times or division numbers.
90. All numbers that are multiples of 3, 5 & 9 are multiples of their lowest common multiple lcm(3, 5, 9) = 45 → multiples of 45 between 49 and 95 is 2 x 45 = 90.
To find numbers that are multiples of both 3 and 5, we need to find the numbers that are common multiples of both 3 and 5. These are numbers that are divisible by the least common multiple of 3 and 5, which is 15. The first four numbers less than 70 that are multiples of both 3 and 5 are 15, 30, 45, and 60.
Any multiple of 15.
Oh, dude, let me break it down for you. So, to find the number of 3-digit multiples of 5, you just gotta figure out the first and last numbers that are multiples of 5 in the 3-digit range, which are 100 and 995. Then you just do some simple math, like subtracting and dividing, and voila, you'll get your answer. It's like counting candy, but with numbers.
No, they are factors of 15. Factors go into numbers, numbers go into multiples.
Multiples of 30
Multiples of 30.