There are three numbers between 10 and 50 which are divisible by both 3 and 5. All numbers that are multiples of 3 and 5 are the multiples of the lowest common multiples (lcm) of 3 and 5 which is 15. The multiples of 15 between 10 and 50 are {15, 30 and 45}, thus there are 3 numbers.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
To find numbers that are multiples of both 3 and 5, we need to find the numbers that are common multiples of both 3 and 5. These are numbers that are divisible by the least common multiple of 3 and 5, which is 15. The first four numbers less than 70 that are multiples of both 3 and 5 are 15, 30, 45, and 60.
Since all 3 are prime numbers LCM = 3 * 5 * 7 = 105 All multiples of 105 are multiples of 3, 5 and 7
If the numbers are multiples of 2, 3, and 5, they are multiples of 2 x 3 x 5 = 30. Here are some multiples of 30: 30, 60, 90, 120, 150, 180, 210, 240, 270, 300, ...
Any multiple of 15.
It is not possible it has to be an even number.Plus it has no times or division numbers.
90. All numbers that are multiples of 3, 5 & 9 are multiples of their lowest common multiple lcm(3, 5, 9) = 45 → multiples of 45 between 49 and 95 is 2 x 45 = 90.
No, they are factors of 15. Factors go into numbers, numbers go into multiples.
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
Multiples of 30
Multiples of 30.