To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
Oh, dude, let me break it down for you. So, to find the number of 3-digit multiples of 5, you just gotta figure out the first and last numbers that are multiples of 5 in the 3-digit range, which are 100 and 995. Then you just do some simple math, like subtracting and dividing, and voila, you'll get your answer. It's like counting candy, but with numbers.
27 three digit numbers from the digits 3, 5, 7 including repetitions.
Only one . . . 999 .
None. The only way for it to be possible would be 3 zeros which is not considered a 3 digit numbers.
There are 5*4*3 = 60 such numbers.
If you want 4-digit numbers, there are 24 of them.
60 numbers
50 of them.
There are 49 3-digit numbers - from 108 to 990 inclusive.
The 3-digit counting numbers are 100 through 999 = 900 numbers.Half them are multiples of 2 (even numbers).The other half are not . . . 450 of them.
45 multiples of 2 plus 30 multiples of 3 minus 15 multiples of 6 equals 60 numbers
There are 36 such numbers.There are 36 of them.
3
There are 75 multiples of 12 between 100 and 1000.
There are 600 such numbers.
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
The smallest 3-digit multiple of 7 is 105 = 15*7 The largest 3-digit multiple of 7 is 994 = 142*7 So there are 142-14 = 128 3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.
there are five choices for each position, so 5^3 or 125 numbers.