27 three digit numbers from the digits 3, 5, 7 including repetitions.
Only one . . . 999 .
None. The only way for it to be possible would be 3 zeros which is not considered a 3 digit numbers.
There are 5*4*3 = 60 such numbers.
If you want 4-digit numbers, there are 24 of them.
60 numbers
50 of them.
There are 49 3-digit numbers - from 108 to 990 inclusive.
The 3-digit counting numbers are 100 through 999 = 900 numbers.Half them are multiples of 2 (even numbers).The other half are not . . . 450 of them.
45 multiples of 2 plus 30 multiples of 3 minus 15 multiples of 6 equals 60 numbers
There are 36 such numbers.There are 36 of them.
3
There are 75 multiples of 12 between 100 and 1000.
There are 600 such numbers.
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
The smallest 3-digit multiple of 7 is 105 = 15*7 The largest 3-digit multiple of 7 is 994 = 142*7 So there are 142-14 = 128 3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.
there are five choices for each position, so 5^3 or 125 numbers.