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What is consecutive odd integers?
For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.
What does (2n)3 equal in properties of exponents.?
2n x 2n x 2n = 8n^3
How do you do 13-2n in sequences terminology?
15
Find 4 consecutive even integers such that twice the least increased by the greatest 96?
The four numbers will be 2n, 2(n + 1), 2(n + 2), and 2(n + 3), such that: 2 * 2n + 2(n + 3) = 96 6n = 90 n = 15 So the four numbers are 30, 32, 34, and 36
What is 2n plus 6 equals 7n - 9?
I'm assuming you are solving for n.2n + 6 = 7n - 9 {add nine to each side}2n + 15 = 7n { subtract 2n from each side}15 = 5n {divide each side by 5}3 = n
What are 4 positive odd numbers whose sum of their squares equals 164?
Answer is 3, 5, 7, 9detailsassume the numbers are2n-3, 2n-1, 2n+1, 2n+3 ......................... (1)(2n-3) 2 + (2n-1) 2 + (2n+1) 2 + (2n+3) 2 = 16416n 2 + 20 = 16416n 2 = 144n2 = 9n = 3Substitute in eq 1 we get the answer above
What is the greatest whole number that MUST be a factor of the sum of any six consecutive positive odd numbers?
Oh, dude, the greatest whole number that MUST be a factor of the sum of any six consecutive positive odd numbers is 3. Why? Because any set of consecutive odd numbers will include multiples of 3, ensuring that the sum will be divisible by 3. So, like, 3 is the magic number here.
What two numbers go in 45 when multiypied bujt also go into -18 when added?
27
What is consecutive odd integers?
For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.
Why are 3 5 and 7 are the only three consecutive odd prime numbers?
This is because at least one of them must be divisible by 3. The outline proof is as follows: Consider the consecutive odd numbers, 2n+1, 2n+3, 2n+5 ... Suppose 2n+1 is divisible by 3. That is 2n+1 = 3k for some integer k, then 2n+7 = (2n+1)+6 = 3k+6 = 3*(k+2) so that 2n+7 is also divisible by 3. So the run stops with 2n+3, 2n+5. Suppose, instead, that 2n+1 leaves a remainder of 1 when divided by 3. Then 2n+3 and 2n+9 etc are divisible by 3. Again leaving a run of only two consecutive odd primes. Finally, suppose that 2n+1 leaves a remainder of 2 when divided by 3. Then 2n+5, 2n+11 etc are divisible by 3 leaving runs of two consecutive odd primes.
What does (2n)3 equal in properties of exponents.?
2n x 2n x 2n = 8n^3
How do you do 13-2n in sequences terminology?
15
What is 5 over 2n plus 3 over 3n?
15/6n + 6/6n = 21/6n = 7/2n
Find 4 consecutive even integers such that twice the least increased by the greatest 96?
The four numbers will be 2n, 2(n + 1), 2(n + 2), and 2(n + 3), such that: 2 * 2n + 2(n + 3) = 96 6n = 90 n = 15 So the four numbers are 30, 32, 34, and 36
What is 2n plus 6 equals 7n - 9?
I'm assuming you are solving for n.2n + 6 = 7n - 9 {add nine to each side}2n + 15 = 7n { subtract 2n from each side}15 = 5n {divide each side by 5}3 = n
What is the nth term rule of the linear sequence below 7 9 11 13 15 . . .?
The nth term is 2n+5 and so the next number is 17
Find two positive integers where one is 3 more than twice the other and their product is 90?
Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.
