The factors are 2n(4n + 3).
4/3=1 1/3
5-2=3n=3
Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.
If that's n squared, the multiples are n squared, 2 n squared, 3 n squared and so on. If that's n + 2, the multiples are n + 2, 2n + 4, 3n + 6 and so on.
3 + 3n = 9 + 2n + 4n n = -2
3n + 9 = 3(n + 3)
3n - 2n = n 3n - 2n = (3 - 2)n = 1n = n
3n+3=n+7 3n+3-n=n+7-n (subtract n from both sides) 2n+3=7 2n+3-3=7-3 (subtract 3 from both sides ) 2n=4 2n/2=4/2 (divided by 2 on both the sides) n=2 Answer: n=2
5N + 3 Just add the Ns and put +3 on the end!
If you mean: (2n-14)(3n+9) = 0 then it is a quadratic equation whose solution is n = -3 or n = 7
5n + 1 = 10 + 2n5n - 2n + 1 - 1 = 10 - 1 + 2n - 2n3n = 93n/3 = 9/3n = 3
The question seems ambigous, but I will consider n 2n to be solving for n:2n - 3n = n/3 + 14-n = n/3 + 14-3n = n + 42-4n = 42Thus, the solution is n = -42/4 = -21/2 = -10.5.
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
The expression m^2n^3/p^3 divided by mp/n^2 can be simplified as (m^2n^3/p^3) / (mp/n^2). This simplifies to (m^3n^5)/(p^3n) = m^3n^4/p^3.
41 - 2n = 2 + n Add 2n to each side: 41 = 2 + 3n Subtract 2 from each side: 39 = 3n Divide each side by 3: 13 = n
7-2n=n-147-2n+2n=n-14+2n7=3n-147+14=3n21=3n21/3=3n/37=n