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Irrational numbers.
None. There is nobody to whom triangular numbers belong.
Rational numbers.
mixed numbers
No, they can belong to infinitely many subsets.
The inequality sign is neglected due to the omitted punctuation for the question. Assume x + 8 ≤ 14. Then, subtract both sides to get: x ≤ 6. If x + 8 < 14, then x < 6. If x + 8 > 14, then x > 6. If x + 8 ≥ 14, then x ≥ 6.
Both belong to set of whole numbers. There are infinite prime and composite numbers.
The set of numbers which 3 does not belong is the set of even numbers.
10 belongs to the set "natural numbers", but it can also belong to whole numbers, and rational numbers
Composite numbers are the non prime numbers and have more than 2 factors. Some examples of composite numbers are 6, 8, 55 etc.
Rational numbers
Counting numbers
Irrational numbers.
x + 9 = 26Only one lonely number belongs to the group of solutions of this equation.The number is 17.
odd numbers, perfect square numbers
None. There is nobody to whom triangular numbers belong.
rational and prime numbers