6 is the only number from 2-7
Yes. Test a couple numbers divisible by 9--27, 81--and they are all divisible by 3.
27 is one of them.
27 is divisible by three because the sum of 2 and 7 is divisible by three. However, this trick only works with the numbers 3 and 9. 27 divided by 3 is 9.
621 is divisible by these numbers: 1, 3, 9, 23, 27, 69, 207, 621.
For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
There are 27 such numbers.
1, 3, 9, 27, 81
Many odd numbers are divisible by 3. 3 itself for example, as well as 9, 15, 21, 27, ... Being odd and being divisible by three are not related.
Yes. It equals 45. A quick rule for numbers to see if they are divisible by 3 is to add all the numbers, for example: 207 = 2 + 0 + 7 = 9 Is 9 divisible by 3...Yes! It helps reduce the large numbers, for an easier answer. The number 8649... 8 + 6 + 4 + 9 = 27 and 27 is divisible by 3, so 8649 is also divisible by 3. BUT...137: 1 + 3 + 7 = 11 11 is not divisible by 3...so, 137 is not divisible by 3.
27 is composite as it is divisible by 1, 3, 9 and 27
The list is infinite but two of them are 54 and 81.
27 and 54 are composite numbers because both are divisible by 3.