27 is divisible by three because the sum of 2 and 7 is divisible by three. However, this trick only works with the numbers 3 and 9.
27 divided by 3 is 9.
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A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, 27 = 2 + 7 = 9/3 = 3. Therefore, 27 is divisible by 3.If the sum of the digits of the number in question is divisible by three, the whole number is divisible by three.
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
Yes. Test a couple numbers divisible by 9--27, 81--and they are all divisible by 3.
Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27 Check for 945: 94-(8*5)=54; 5-(8*4)=-27 Since 27 is divisible by 27, the original no. 945 is also divisible. Check for 264681: 26468-(8*1)=26460; 2646-(8*8)=2582; 264-(8*6)=216 21-(8*6)=-27 Since 27 is divisible by 27, the original no. 264681 is also divisible. Check for 81: 8-(8*1)=0; Since 0 is divisible by 27, the original no. 81 is also divisible.
No, 83 is not divisible by 3. When a number is divisible by another number, it means that the division will result in a whole number without a remainder. In this case, when you divide 83 by 3, you get 27 with a remainder of 2, which means 83 is not divisible by 3.