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When you subtract a square number from another the answer is 3 what are the 2 numbers?
1 x 1 = 1 2 x 2 = 4 4 - 1 = 3 Answer: the numbers are 1 and 2
Find the two numbers whose product is 1 and whose sum is 1?
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
When you subtract one square number from the other the answer is 3 what are the 2 square numbers?
They are 1 and 4.
What 2 rational numbers are between square root of 3?
There are 2 square roots of 3, denoted by -sqrt(3) and +sqrt(3). Then -sqrt(3) < -1 and 1/5 < sqrt(3)
What type of numbers are these 1 4 9 16 25?
These are square numbers. 1, 4, 9, 16, 25 1 2, 2 2, 3 2, 4 2, 5 2, next number is 6 2 = 36
What three square numbers add together makes another square number?
One well-known example of three square numbers that add together to form another square number is (1^2), (2^2), and (3^2). Specifically, (1 + 4 + 9 = 14), which is not a square. However, (0^2 + 1^2 + 2^2 = 0 + 1 + 4 = 5), which is also not a square. A valid combination is (1^2 + 2^2 + 3^2 = 1 + 4 + 9 = 14), which does not yield a square. The true example is (1^2 + 2^2 + 3^2 = 14), which is the sum of (1^2 + 2^2 + 3^2), leading to (5^2).
What three one digit numbers have a palindrome as the square number?
1, 2, 3
What is the square root of -45 using imaginary numbers?
Square root of -45 = (-45)1/2 = (-3x3x5)1/2 = 3(-5)1/2 = 351/2i
Are all perfect square number are even numbers?
No, all perfect square numbers are not even numbers. Eg. the square of 3 is 9. (32=9) To generalize the proof: If p is odd then p=2n+1 and p2=(2n+1)2=4n2+4n+1=2(2n2+2n)+1 So odd numbers have odd square
What are examples of perfect square roots?
Perfect square roots are the counting numbers {1, 2, 3, ...} The squares of the perfect square roots are the perfect squares, namely 1² = 1, 2² = 4, 3² = 9, etc.
What square number comes after 16?
25. Square numbers are numbers that result from integers being raised to the power of 2. 1^2 = 1. 1 is the first square number. 2^2 = 4. 4 is the second. 3^2 = 9. 4^2 =16. 5^2 = 25.
What are the square numbers to 169?
Just calculate: 1 x 1 = 1 2 x 2 = 4 3 x 3 = 9 etc.
