There are 2 square roots of 3, denoted by -sqrt(3) and +sqrt(3). Then
-sqrt(3) < -1 and 1/5 < sqrt(3)
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There are no rational numbers between sqrt(-26) and sqrt(-15). The interval comprises purely imaginary numbers.
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Write both numbers as decimal numbers, then look for terminating decimals between the two.
There are an infinite number of rational numbers between these two numbers, but the only positive integer between these numbers is 6.
Only if the square root of the numerator and the square root of the denominator are both rational numbers.