(4,1)
y2x is an expression, which cannot be graphed because we don't know what it equals. y = 2x, y2 = x, and 2y (or y2) = x are all things that could actually be graphed.
Points: (x1, y1) and (x2, y2) Slope: y1-y2/x1-x2
Points: (x, y) and (x2, y2) Slope = y2-y divided by x2-x
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
Two points: (x1, y1) and (x2, y2), Then formula would be: y2 - y1 (over) x2 - x1
two points form a line. (x1,y1)(x2,y2)
1
The slope between two points, (x1, y1) and (x2, y2) is: (y1 - y2) / (x1 - x2)
The Pythagorean Theorem. Consider the right triangle including the two points and a third point having the same x coordinate as one and the same y coordinate as the other. Apply the Pythagorean theorem. For (x1, y1) and (x2,y2): dist. = sqrt((x1-x2)2 + (y1-y2)2)
For the following formula, m=slope and /=fraction bar. Given points: (x1,y1) and (x2,y2). m = y2 - y1/x2 - x1
Distance = the square root of (x2-x1)2 + (y2-y1)2Added:Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squared
The distance between two points, (x1,y1) , (x2,y2) = squareroot[(x2-x1)2 + (y2-y1)2]