Wiki User
∙ 12y agoThe Pythagorean Theorem. Consider the right triangle including the two points and a third point having the same x coordinate as one and the same y coordinate as the other. Apply the Pythagorean theorem.
For (x1, y1) and (x2,y2): dist. = sqrt((x1-x2)2 + (y1-y2)2)
Wiki User
∙ 12y agoWhen a line segment connecting two points is horizontal the length of the segment can be found by finding the absolute value of the difference in x-coordinates of the two points.
The slope of a line is the rise divided by the run. In other terms, if, X = the horizontal distance between two points on a line and Y = the vertical distance between the same points, then m = Y/X
ruler
If you know the end points then use the distance formula or simply use a ruler.
True
Horizontal
x-coordinates :)
To find the distance on a coordinate map, you can use the Pythagorean theorem to calculate the shortest distance between two points. Simply calculate the horizontal and vertical differences between the points, then use these differences as the sides of a right triangle to find the distance.
When a line segment connecting two points is horizontal the length of the segment can be found by finding the absolute value of the difference in x-coordinates of the two points.
Add the x-coordinates of the points and take the absolute value
The slope of a line is the rise divided by the run. In other terms, if, X = the horizontal distance between two points on a line and Y = the vertical distance between the same points, then m = Y/X
It is used, except that, because one set of coordinates are the same, the formula collapses into a simpler form.
It is used, except that, because one set of coordinates are the same, the formula collapses into a simpler form.
ruler
how do you find distance between points
Subtract the x-coordinates of the points and take the absolute value. Using the Pythagorean Theorem, the y-value would be zero, and the distance the square root of its own square.
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.