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Q: Which step would not be a possible first step for solving the following equation algebraically?

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You get the exact solution.

That's an extraneous solution. You need to check for these when algebraically solving equations, especially when you take both sides of an equation to a power.

yes

Yes it is quite possible

What role of operations that applies when you are solving an equation does not apply when your solving an inequality?"

No because you always keep an equation in balance when solving it

It is the solution of the equation

Methods vary considerably depending upon the number of powers in the equation. For example, the method for solving cubics is quite different to solving quadratics etc... It's not really possible to generalise to one technique.

Ask someone eles.

It is known as solving the equation.

An equality and equation are essentially the same thing. The equality between two expressions is represented by an equation (and conversely).

5R=45

finding the soultion or answer .

Yes

Using the quadratic equation formula is a method of solving quadratic equations.

Some operations cannot be done. For example, if we take the equation x=2/0, there is no result, because division by 0 is not defined.

An equation is a mathematical statement that may (or may not) be true, defined for some variables. Solving an equation is finding those values of the variables for which the equation or statement is true.

With Your Fingers

solution

Through a process called solving the equation. How do I solve the equation

Put simply, the equation for solving a cubic equation is x2 + 2ax +b = (x+a)2 + b-a2. This leads to x = -a +/- (a2 -b)1/2.

0.025

Because linear equations are based on algebra equal to each other whereas literal equations are based on solving for one variable.

It is important to check your answers to make sure that it doesn't give a zero denominator in the original equation. When we multiply both sides of an equation by the LCM the result might have solutions that are not solutions of the original equation. We have to check possible solutions in the original equation to make sure that the denominator does not equal zero. There is also the possibility that calculation errors were made in solving.

Yes