Which two consecutive numbers have a product of 9120?

Answer 1

Two consecutive numbers can be represented as n and (n + 1), then :-

n(n + 1) = 9120

n² + n - 9120 = 0 . . . this can be factored as,

(n + 96)(n - 95) = 0 . . . so the two numbers are 95 and 96 (or -96 and -95).