Find two consecutive numbers with the value of 4160
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Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.
15 and 13
11 and 12
The numbers are 8 and 9.
Let's denote the two consecutive numbers as x and x+1. The product of two consecutive numbers is given by x(x+1). We are given that x(x+1) = 6162. By solving this equation, we find that x = 78. Therefore, the two consecutive numbers are 78 and 79, as 78 * 79 = 6162.