Q: Which two factors of 48 have a sum of 19?

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16 and 3

48

the answer is 67

43 and 5 41 and 7 37 and 11 31 and 17 29 and 19

If the two numbers have a hcf of 48 then both numbers must be multiples of 48. 384 ÷ 48 = 8 .........Taking the paired factors of 48 of both numbers then the sum of the other factors = 8 but there can be no other common factor. 1 + 7 = 8, 3 + 5 = 8 are solutions but 2 + 6 = 8 and 4 + 4 = 8 are not, as further common factors of 2 and 4 respectively are present which would increase the hcf to 96 and 192. The numbers are 1 x 48 and 7 x 48 → 48 and 336 and.....................3 x 48 and 5 x 48 → 144 and 240

Related questions

24 and 16 are factors of 48

They are: 29+19 = 48

24 & 2 Factors of 48, that is, the 2 numbers that when multiplied together equal 48 are: a) 1 & 48; sum is 49 - nope b) 2 & 24; sum is 26 - ding! ding! ding! ding! c) 3 & 16; sum is 19 - nope d) 4 & 12; sum is 16 - nope e) 6 & 8; sum is 14 - nope

16 and 3

16 and 3

16 and 3

48

A "factor" is an integer that can be divided into another number. For instance, 3 is a factor of 6. All you needed to do was list all the factor pairs of 48, and see which ones add up to 19: 1 x 48 2 x 24 3 x 16 You can stop here, because 3+16=19. Therefore, your two numbers are 3 and 16.

24 and 2 2 X 24=48 2+24=26

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. Their sum is 124.

48

67