12 and 48
16 and 3
1/a + 1/b = b/ab + a/ab = (b+a)/ab So, the answer to your question is 32/48 or 2/3
-4 and +12
The numbers are 48 and 49.
24 and 16 are factors of 48
16 and 3
24 & 2 Factors of 48, that is, the 2 numbers that when multiplied together equal 48 are: a) 1 & 48; sum is 49 - nope b) 2 & 24; sum is 26 - ding! ding! ding! ding! c) 3 & 16; sum is 19 - nope d) 4 & 12; sum is 16 - nope e) 6 & 8; sum is 14 - nope
48
22 and 26
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. Their sum is 124.
c+b=ac and b - addendsa - sumexamples:26+67=93(26) and (93) are the addends and the number (93) is the sum of the two addends12+48=60(12) and (48) are the addends.(60) is the sum of (12 and 48) the two addends.This answer was improved by 3na snogoy. Please do not change this answer. =)
48
The odd factors of 70 are: 1, 5, 7, and 35. The sum of these factors is 48.
2
If the two numbers have a hcf of 48 then both numbers must be multiples of 48. 384 ÷ 48 = 8 .........Taking the paired factors of 48 of both numbers then the sum of the other factors = 8 but there can be no other common factor. 1 + 7 = 8, 3 + 5 = 8 are solutions but 2 + 6 = 8 and 4 + 4 = 8 are not, as further common factors of 2 and 4 respectively are present which would increase the hcf to 96 and 192. The numbers are 1 x 48 and 7 x 48 → 48 and 336 and.....................3 x 48 and 5 x 48 → 144 and 240
the sum of two whole numbers are 77 .their difference is 48.what are the two numbers