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If the quotient of two numbers is 4 and their sum is 60. What are the two numbers?
12 and 48
What two numbers have the product of 48 and sum of 19?
16 and 3
The sum of two numbers is 32 and the product of these two numbers is 48 what is the sum of the reciprocal of the two numbers?
1/a + 1/b = b/ab + a/ab = (b+a)/ab So, the answer to your question is 32/48 or 2/3
What two numbers can you multiply to get a product of -48 and a sum of 8?
-4 and +12
What is the sum of two consecutive whole numbers of 97?
The numbers are 48 and 49.
What are two factors of 48 with a sum of 26?
24 and 16 are factors of 48
Which two factors of 48 have a sum of 19?
16 and 3
What are two factors of forty eight with a sum of twenty six?
24 & 2 Factors of 48, that is, the 2 numbers that when multiplied together equal 48 are: a) 1 & 48; sum is 49 - nope b) 2 & 24; sum is 26 - ding! ding! ding! ding! c) 3 & 16; sum is 19 - nope d) 4 & 12; sum is 16 - nope e) 6 & 8; sum is 14 - nope
What is the sum of all the factors of 35?
48
Find two numbers whose sum is 48 and whose difference is 4?
22 and 26
What is the sum of all the factors of 48?
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. Their sum is 124.
What is the parts of the addition?
c+b=ac and b - addendsa - sumexamples:26+67=93(26) and (93) are the addends and the number (93) is the sum of the two addends12+48=60(12) and (48) are the addends.(60) is the sum of (12 and 48) the two addends.This answer was improved by 3na snogoy. Please do not change this answer. =)
What is the sum of the proper factors of 75?
48
What is the sum of all of the odd factors of 70?
The odd factors of 70 are: 1, 5, 7, and 35. The sum of these factors is 48.
What are the common factors of 60 26 48?
2
The sum of two numbers is 384what are the possible numbers if their HCF is 48?
If the two numbers have a hcf of 48 then both numbers must be multiples of 48. 384 ÷ 48 = 8 .........Taking the paired factors of 48 of both numbers then the sum of the other factors = 8 but there can be no other common factor. 1 + 7 = 8, 3 + 5 = 8 are solutions but 2 + 6 = 8 and 4 + 4 = 8 are not, as further common factors of 2 and 4 respectively are present which would increase the hcf to 96 and 192. The numbers are 1 x 48 and 7 x 48 → 48 and 336 and.....................3 x 48 and 5 x 48 → 144 and 240
Find two numbers whose sum is 48 and whose difference is 26?
Two ways to do this: x + y = 48 y = 48-x x - y = 26 x - 48 + x = 26 2x = 74 x = 37 y = 48-37 = 11 so 37 and 11 Other method x + y=48 x - y=26 Subtract line 1 from line 2 2y = 22 y = 11 then solve for x x +11=48 x = 37 again you get 37 and 11
