No one can because its discriminant is less than zero
(2x+3)(2x+4)
(2x-1)(2x-1) = 4x^2 -4x + 1
(2x - 3)(2x - 3)
There is no rational factorisation.
2(x - 1)(2x + y)
(4x + 1)(2x + 3)
The answer is (2x^2+3)(4x+1)
(2x - 9)(2x - 9) or (2x - 9)2
(2x - 1)(6x + 5)
2x(2x - 1)
It is: 4x squared
-x2+2x