The equation for amperage when the kilowatts are known is Amps = kVA x 1000/1.73 x Volts.
The electrical code states that a feeder for a transformer has to be rated at 125% for the primary and secondary load amperages.
The amperage on the primary needed to supply a 70 KVA three phase transformer to its full capacity at 600 will be 68 amps. 68 x 125% = 85 amps. A #4 copper conductor with an insulation factor of 90 degrees C is rated at 95 amps.
The amperage on the secondary needed to supply a 70 KVA three phase transformer to its full capacity at 480 will be 84 amps. 84 x 125% = 105 amps. A # 3 copper conductor with an insulation factor of 90 degrees C is rated at 115 amps.
The equation you are looking for is amperage = kva x 1000/1.73 x voltage.150 x 1000 = 150000/1.73 x 480 = 150000/830 = 180 amps for primary side of transformer.150 x 1000 = 150000/1.73 x 240 = 150000/415 = 361 amps for the secondary side of the transformer.The electrical code requires transformers and motors conductors to be sized at 125% of the rated amperage.So 180 x 125% = 225 amps, and 361 x 125% = 451 amps.A 3/0 copper conductor with an insulation factor of 90 degrees C is rated at 225 amps.A 600 MCM copper conductor with an insulation factor of 90 degrees C is rated at 475 amps.Parallel 3/0 copper conductors with an insulation factor of 90 degrees C will give a capacity of 450 amps.There is no 2 phase 240 volt secondary.Any two legs of a three phase system are classified as single phase. Single phase 240 volts can be obtained from any of the following transformer tap connections, A-B, B-C, C-A.
Wire sizing of a feed conductor is based on the amperage that a device draws. To calculate amperage from KVA a voltage of the supply has to be stated. Without this voltage and whether the transformer is single or three phase an answer can not be given.
Yes, # 4 AWG copper and 100 amps is the max.
Not directly, you would need to transform 480v circuit to 120v with a transformer first.
500 mcm (or 500kcmil) conductors are used for 400 amp 480v single phase or 3 phase systems. The wire AND THE TERMINALS must be rated for 90o Celsius.
What size breakers are needed for a 30kva transformer 208 volt feed 600 volt out put
If the primary and the secondary windings of the three phase transformer are connected in delta, you cannot get a healthy neutral from it but why bother? You simply drive a rod into earth and use it as a neutral. Alternatively either the primary or the secondary windings must be connected as star and you use the common point as neutral.
The equation you are looking for is amperage = kva x 1000/1.73 x voltage.150 x 1000 = 150000/1.73 x 480 = 150000/830 = 180 amps for primary side of transformer.150 x 1000 = 150000/1.73 x 240 = 150000/415 = 361 amps for the secondary side of the transformer.The electrical code requires transformers and motors conductors to be sized at 125% of the rated amperage.So 180 x 125% = 225 amps, and 361 x 125% = 451 amps.A 3/0 copper conductor with an insulation factor of 90 degrees C is rated at 225 amps.A 600 MCM copper conductor with an insulation factor of 90 degrees C is rated at 475 amps.Parallel 3/0 copper conductors with an insulation factor of 90 degrees C will give a capacity of 450 amps.There is no 2 phase 240 volt secondary.Any two legs of a three phase system are classified as single phase. Single phase 240 volts can be obtained from any of the following transformer tap connections, A-B, B-C, C-A.
Wire sizing of a feed conductor is based on the amperage that a device draws. To calculate amperage from KVA a voltage of the supply has to be stated. Without this voltage and whether the transformer is single or three phase an answer can not be given.
Yes you could use a 20 kva transformer in a home. Stymied as to why it would be done though. You would need at least a 100 amp service to the home to energize the transformer. Primary side of the transformer would draw 83 amps at 240 volts. If the question was to supply the home, again yes. It would be 100 amp service equipment that the transformer would feed into.
watts = amps x volts400amps x 480V = 192,000 watts192,000/1000 = 192KWYou would need 192KW generator at 277/480 The formula for kilowatts is, kW = I x E x 1.73 x pf/1000. kW = 400 x 480 x 1.73 .90 = 298944/1000 = 298.9 or 300 kW generator.
This terminology usually refers to pad mounted transformers. A "radial feed " transformer is a transformer that has one bushing for the high voltage cable line. The high voltage cable terminates into the transformer through the transformer's bushing. There is no second bushing for the high voltage cable to continue further down the line. This type of transformer is usually on the end of a loop feed circuit. This is different from a "loop feed" transformer whose incoming cables are terminated at the primary bushings. On this type of transformer there is a second bushing which connects to the outgoing primary voltage cables that allows the primary to feed another transformer. Each pad mount transformer's secondary feed usually supplies enough power to connect up to four homes.
The lamp uses 240 x 4.9 VA, that is 1176 VA, so a 15 kVA transformer, which is 15,000 VA, could feed 12 lamps.
These transformers are usually reciprocal, and don't care which side you feed. Some caveats may apply if there are cooling fans, the other voltage is 100KV, this is connected as a wye to high-delta converter and so on.
A #3 copper conductor with an insulation factor of 90 degrees C is rated at 115 amps.
your not completing the circuit your only using one phase for a three phase motor
No, pull in a separate feed for the single phase receptacle.