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Q: Whose work is best characterized by the use of solid volumes resting firmly on the flat and horizontal surface of this earth?
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Related questions

What phase of the mesocycle characterized by high levels of intensity and reduced volumes of work?

endurance


What properties of solids determine the volumes and surface area?

Resistance to deformation.


Is it possible to have two shapes with the same surface area but different volumes?

Absolutely.


Surface areas and volumes of spheres?

The formula for the surface area of a sphere is 4πr2. The formula for the volume of a sphere is 4/3πr3.


How can two rectangular prisms have the same surface area but different volumes?

Yes, they can. They can also have the same surface area, but different volume.


Volumes of 2-D dimensional figures?

2D figures have surface area, but no volume.


Can you have 2 different rectangular prisms with the same Surface area but different volumes?

Yes, you can.


How do you calculate Triangular prisms?

The answer to the question depends on whether you want to calculate the surface areas or the volumes, or some other measure.


One advantage of the prismoidal formula is that you can use it to Acalculate precise volumes of all prismoids Bcalculate both volume and surface area Cdetermine volumes of figures that are not prismoi?

estimate the volume of solids that are combinations of other solids


How do you calculate surface area to volume ratio?

You measure or calculate the surface area; you measure or calculate the volume and then you divide the first by the second. The surface areas and volumes will, obviously, depend on the shape.


What are the basic volumes?

basic volumes are volumes that are original


The volumes of two similar figures are 512 mm3 and 3375mm3. If the surface area of the smaller figure is 128mm2. What is the surface area of the larger figure?

450 mm2 Ratio of areas is the square of the ratio of lengths. Ratio of volumes is the cube of the ratios of lengths. If the volumes are in the ratio of 512 to 3375, then the lengths are in the ratio of: 3√512 : 3√3375 = 8 : 15 ⇒ ratios of areas: 82 : 152 = 64 : 225 ⇒ as smaller has surface area of 128 mm2, the larger has: surface_area = (128 ÷ 64) x 225 mm2 = 450 mm2