The calculation is equal to the sum of their probabilities less the probability of both events occuring. If two events are mutually exclusive then the combined probability that one or the other will occur is simply the sum of their respective probabilities, because the chance of both occurring is by definition zero.
yes P(AUB)=P(A)+P(B) but only for mutualy exclusive events
The sum is 1
The sum of the probability of success and the probability of failure had better equal 1.00 (100%) or an error has been committed.
The answer depends on what you mean by "do". Does it mean calculate individually, calculate the probability of either one or the other (or both), calculate the probability of both, calculate some function of both (for example the sum of two dice being rolled)?
The answer depends on the sum of WHAT!
It is the integral (or sum) of the joint probability distribution function of the two events, integrated over the domain in which the condition is met.
The probability that the sum of two dice is 7 is 6 in 36, or 1 in 6.Of all the combinations, this is the one with the highest probability.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
When considering the probability of two different events or outcomes, it is essential to clarify whether they are mutually exclusive or independent. If the events are mutually exclusive, then the probability that either one or the other will occur equals the sum of their individual probabilities. This is known as the law of addition. If, however, two or more events or outcomes are independent, then the probability that both the first and the second will occur equals the product of their individual probabilities. This is known as the law of multiplication.
The probability of not rolling a sum of six with two fair dice is 1 minus the probability of rolling a sum of six. There are 36 permutations of rolling two dice. Of these, five sum to six, 1+5, 2+4, 3+3, 4+2, and 5+1. The probability, then of rolling a sum of six is 5 in 36. The probability, then of not rolling a sum of six is 31 in 36, or about 0.8611.
The answer is zero !