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The calculation is equal to the sum of their probabilities less the probability of both events occuring. If two events are mutually exclusive then the combined probability that one or the other will occur is simply the sum of their respective probabilities, because the chance of both occurring is by definition zero.
To find the probability of rolling a sum of six followed by a sum of eight with two six-sided dice, we first calculate each individual probability. The probability of rolling a sum of six is 5/36, and the probability of rolling a sum of eight is 5/36 as well. Since these events are independent, we multiply the probabilities: (5/36) * (5/36) = 25/1296. Thus, the probability of rolling a sum of six followed by a sum of eight is 25/1296.
yes P(AUB)=P(A)+P(B) but only for mutualy exclusive events
The sum is 1
The sum of the probability of success and the probability of failure had better equal 1.00 (100%) or an error has been committed.
The four basic rules of probability are: Non-negativity: The probability of any event is always between 0 and 1, inclusive. Normalization: The total probability of all possible outcomes in a sample space sums to 1. Additive Rule: For mutually exclusive events, the probability of either event occurring is the sum of their individual probabilities. Multiplicative Rule: For independent events, the probability of both events occurring is the product of their individual probabilities.
The answer depends on the sum of WHAT!
The answer depends on what you mean by "do". Does it mean calculate individually, calculate the probability of either one or the other (or both), calculate the probability of both, calculate some function of both (for example the sum of two dice being rolled)?
It is the integral (or sum) of the joint probability distribution function of the two events, integrated over the domain in which the condition is met.
The probability that the sum of two dice is 7 is 6 in 36, or 1 in 6.Of all the combinations, this is the one with the highest probability.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
The probability of not rolling a sum of six with two fair dice is 1 minus the probability of rolling a sum of six. There are 36 permutations of rolling two dice. Of these, five sum to six, 1+5, 2+4, 3+3, 4+2, and 5+1. The probability, then of rolling a sum of six is 5 in 36. The probability, then of not rolling a sum of six is 31 in 36, or about 0.8611.