The probability that the sum of two dice is 7 is 6 in 36, or 1 in 6.
Of all the combinations, this is the one with the highest probability.
Te probability of rolling a sum of 7 with two fair dice is 6 in 36, or 1 in 6, or about 0.1667.Of all the possible combinations of two dice, the sum of 7 has the highest probability, with the other combinations decreasing down to 2 and 12, with probabilities of 1 in 36, or about 0.0278.
Probability(Total = 7) = 15/216 = 0.069 Probability(Total = 13) = 21/216 = 0.097
-- There are (6 x 6) = 36 possible rolls for a fair pair of 6-sided dice.-- There are 6 ways to roll a sum of 7 :1 ... 62 ... 53 ... 44 ... 35 ... 26 ... 1-- So the probability is 6/36 = 1/6 = 162/3 % .-- The probability is the probability, not the 'theoretical' probability.
When a tetrahedral die is rolled, it will rest with three faces upwards. If the die is numberd from 1 to 4. therefore the sum of the upward facing numbers on 1 die is at least 6 and so for two dice, the minimum is 12. That being the case, the probability is 0.
Part1: Finding probability of getting sum as a perfect square. Maximum sum of both the dice is (6+6) equal to 12. Up to 12, the perfect squares are: 1, 4 and 9. Getting a sum of 1 from two dice is not possible. So, we are left with 4 and 9. To get 4, the combination can be: (2,2) or (1,3) or (3,1). This means, to get the sum as 4, the probability is [3/36]. To get 9, the combination can be: (3,6) or (6,3) or (5,4) or (4,5). This means, to get the sum as 9, the probability is [4/36]. Therefore,the total probability of getting the sum as a perfect square is: [(3/36)+(4/36)]=[7/36]. Part2: Finding the probability of getting sum as an even number. The possible even numbers can be 2, 4, 6, 8, 10 and 12. But, as 4 is already considered in part1, it should be ignored in this case. The probability of getting sum as 2 is: [1/36] The probability of getting sum as 6 is: [5/36] The probability of getting sum as 8 is: [5/36] The probability of getting sum as 10 is: [3/36] By adding all the above, the probability of getting sum as an even number (ignoring 4) is: [(1/36)+(5/36)+(5/36)+(3/36)]=[14/36]. From part 1 and part 2, we get the total probability as [(7/36)+(14/36)]=[7/12]=0.583333.
The probability is 1/6.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
There are 216 permutations of three dice. Of these, 15 sum to 7. Therefore, the probability of rolling a sum of 7 with three dice is 15 in 216, or 5 in 72, or about 0.06944.111112113114115711612112212312471251261311321337134135136141142714314414514615171521531541551561611621631641651662112122132147215216221222223722422522623123272332342352362417242243244245246251252253254255256261262263264265266311312313731431531632132273233243253263317332333334335336341342343344345346351352353354355356361362363364365366411412741341441541642174224234244254264314324334344354364414424434444454464514524534544554564614624634644654665117512513514515516521522523524525526531532533534535536541542543544545546551552553554555556561562563564565566611612613614615616621622623624625626631632633634635636641642643644645646651652653654655656661662663664665666
The probability is 21/36 = 7/12
The probability is 1/6.
7
It depends upon what numbers are on the faces of the dice. Assuming a standard die with faces 1-6 and the four sided die has faces 1-4, then: To get a sum of seven will require: 6-1, 5-2, 4-3 or 3-4 There are 4 successful rolls. There are 6×4 = 24 possible rolls → Probability(sum of 7) = 4/24 = 1/6
Te probability of rolling a sum of 7 with two fair dice is 6 in 36, or 1 in 6, or about 0.1667.Of all the possible combinations of two dice, the sum of 7 has the highest probability, with the other combinations decreasing down to 2 and 12, with probabilities of 1 in 36, or about 0.0278.
Probability(Total = 7) = 15/216 = 0.069 Probability(Total = 13) = 21/216 = 0.097
The answer will depend on what is being tossed!
The probability of any event MUST be a number between 0 and 1. It is not possible to have a probability of 18 or 16. Furthermore, given that the dice are not normal, the question should also specify how many faces they have and what numbers are on these faces.
-- There are (6 x 6) = 36 possible rolls for a fair pair of 6-sided dice.-- There are 6 ways to roll a sum of 7 :1 ... 62 ... 53 ... 44 ... 35 ... 26 ... 1-- So the probability is 6/36 = 1/6 = 162/3 % .-- The probability is the probability, not the 'theoretical' probability.