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Since 6 is an even number, its multiples are all even numbers as well. This means that each of its multiples ends in an even number (0, 2, 4, 6, 8). Since 3 is an odd number, any integer ending in a 3 is odd, thus proving that the number is not a multiple of 6.
cause 6 is even and any number multiply by an even number is even
Obviously any number ending with a 3 is odd
6 = 3 x 2
6 x Z = 3 x 2 x Z so the number is even and therefore cannot ends in 1, 3, 5, 7 or 9
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If a number ends in 5 does it mean it is in the 5 times table?
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