Since 6 is an even number, its multiples are all even numbers as well. This means that each of its multiples ends in an even number (0, 2, 4, 6, 8). Since 3 is an odd number, any integer ending in a 3 is odd, thus proving that the number is not a multiple of 6.
cause 6 is even and any number multiply by an even number is even
Obviously any number ending with a 3 is odd
6 = 3 x 2
6 x Z = 3 x 2 x Z so the number is even and therefore cannot ends in 1, 3, 5, 7 or 9
It will be in the 5 times table but it may be in other times tables like 45 is in the 5 times table and the 9 times table. Also if it ends in a 0 it will be in the 5 times table
Anything that ends in 5 or 0 is in the 5 times table.
No, no multiple of 4 ends in 5; they all end in 0, 2, 4, 6, or 8.
no, if it ends in an odd number it cannot be divided by 4
A vegetable. It ends in "table."
Check it out: 4,8,12,16,20,24,28,32,36. No threes.
0 and 5. Every multiple of 5 ends in one of those 2 digits. 5 times any even number ends in 0; 5 times an odd number ends in 5.
Yes. If a number ends in an odd number, as in 75, any factors cannot be even
Composite. It ends in 5 and so is divisible by 5. So it cannot be a prime.
If a number is divisible by 4, it also means that the same number is divisible by 2. But if the number ends in a 3, it can't be divisible by 2 and, to a further extent, can't be divisible by 4.