Study guides

☆☆

Q: Why a number which ends in 3 cannot be a multiple of 4?

Write your answer...

Submit

Still have questions?

Related questions

Check it out: 4,8,12,16,20,24,28,32,36. No threes.

4 is an even number and so all multiples of 4 must be even. A number ending in 3 is not even and so cannot be a multiple of 4.

No.3 is less than 5, thus cannot be a multiple of it; 3 is prime, therefore cannot be a multiple of any number besides 3 (which is one of its factors); by definition, 3 is ismply not a multiple of any number but 1 and 3.

A number that ends in 3 can't be a multiple of 4 because the 4 times table goes in a pattern, (e.g 4, 8, 12, 16, 20, 24.) If the number ends in either 0 2 4 6 8 then it couldbe a possible multiple of 4. It always ends in an even number. 3 is not an even number so it is not going to be the last number of a multiple of 4.

If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9

All multiples of 6 are even numbers.

No number that is a multiple of 3, can be a prime number. A prime number must only be divisible by itself and 1. It cannot be divisible by any other number. Therefore if it is a multiple of 3, then it must be divisible by 3 and hence, not a prime number.

Since 6 is an even number, its multiples are all even numbers as well. This means that each of its multiples ends in an even number (0, 2, 4, 6, 8). Since 3 is an odd number, any integer ending in a 3 is odd, thus proving that the number is not a multiple of 6. cause 6 is even and any number multiply by an even number is even Obviously any number ending with a 3 is odd 6 = 3 x 2 6 x Z = 3 x 2 x Z so the number is even and therefore cannot ends in 1, 3, 5, 7 or 9

9720

I think so. Because it ends in a 3.

There are different rules for different number 2: ends in 2,4,6,8,0 3: digits add up to multiple of 3 4: last two digits are divisible by 4 5: ends in 5,0 6: follows the rules of both 2 and 3 9: digits add up to a multiple of 9 10: ends in 0

It would help to have that other number. If the other number is a multiple of 3, the LCM is that number. If it is not a multiple of 3, the LCM is 3 times that number.

There is no such number. Since if x were the largest multiple of 3 and 7 then what about 2x? 2x would be a multiple of 3 since x is a multiple of 3; 2x would be a multiple of 7 since x is a multiple of 7; and 2x is bigger than x. So x cannot be the largest.

No. To find if a number is a factor of 3, add the number's digits. If the resulting number is a multiple of 3, then the original number is a multiple of 3. In 4339, the digits of the number added together is 19, which is not a multiple of 3.

There is no answer. There cannot be a lowest common multiple of a single number, such as 30, because "common multiple" means a multiple that two or more numbers have in common. Likewise, there cannot be a highest common factor of a single number, such as 3, because "common factor" means a factor that two or more numbers have in common.

No, 92 is not a multiple of 3. A quick way to check if a number is a multiple of 3 is: add up the digits of the number you are checking; if this sum equals 3 or a multiple of 3, then the number is a multiple of 3. So in this case, 92 --> 9+2=11, which is not a multiple of 3. If you have to you can add again, so for 11 --> 1+1=2, which is not a multiple of 3. You can always repetitively add until you get to a single digit answer: if it's 3,6 or 9 then it's a multiple of 3. Also if your sum is 9 or a multiple of 9, then the original number is a multiple of 9. To check for 6, if a number is a multiple of 3, and also a multiple of 2 (an even number), then the number is a multiple of 6.

Any multiple of 6 is a multiple of 3 and 6.

9 is a multiple of 3. It is 3 x 3.

3 is the smallest number that is a factor 66 and a multiple of 3

you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!

Add up the digits in the number. If the total is a multiple of 3, the entire number will be a multiple of 3.

A multiple of 3.

The digit with which a multiple of 4 ends depends on the last digit of the other factor. If the last digit is a zero, the product ends with zero; if the last digit is a 1, the product ends with 4; etc. The only options for the last digit of the product are 0, 2, 4, 6, 8.

18

It doesn't divide by 2 as it's an odd number, its digits add to a multiple of 3 so it divides by 3: 3 x 17. 17 is a prime number so it ends here.