Best Answer

The digit with which a multiple of 4 ends depends on the last digit of the other factor. If the last digit is a zero, the product ends with zero; if the last digit is a 1, the product ends with 4; etc. The only options for the last digit of the product are 0, 2, 4, 6, 8.

Q: Why a number that ends in a 3 can't be a multiple of 4?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9

All multiples of 6 are even numbers.

A prime number has no factors other than 1 and itself. Each multiple of fifteen includes 3, 5, and 15 among its factors.

No, 92 is not a multiple of 3. A quick way to check if a number is a multiple of 3 is: add up the digits of the number you are checking; if this sum equals 3 or a multiple of 3, then the number is a multiple of 3. So in this case, 92 --> 9+2=11, which is not a multiple of 3. If you have to you can add again, so for 11 --> 1+1=2, which is not a multiple of 3. You can always repetitively add until you get to a single digit answer: if it's 3,6 or 9 then it's a multiple of 3. Also if your sum is 9 or a multiple of 9, then the original number is a multiple of 9. To check for 6, if a number is a multiple of 3, and also a multiple of 2 (an even number), then the number is a multiple of 6.

No. To find if a number is a factor of 3, add the number's digits. If the resulting number is a multiple of 3, then the original number is a multiple of 3. In 4339, the digits of the number added together is 19, which is not a multiple of 3.

Related questions

A number that ends in 3 can't be a multiple of 4 because the 4 times table goes in a pattern, (e.g 4, 8, 12, 16, 20, 24.) If the number ends in either 0 2 4 6 8 then it couldbe a possible multiple of 4. It always ends in an even number. 3 is not an even number so it is not going to be the last number of a multiple of 4.

If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9

Check it out: 4,8,12,16,20,24,28,32,36. No threes.

All multiples of 6 are even numbers.

Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.

4 is an even number and so all multiples of 4 must be even. A number ending in 3 is not even and so cannot be a multiple of 4.

If a number is divisible by 4, it also means that the same number is divisible by 2. But if the number ends in a 3, it can't be divisible by 2 and, to a further extent, can't be divisible by 4.

Because the multiples of 4 are even numbers and 3 is an odd number

There are different rules for different number 2: ends in 2,4,6,8,0 3: digits add up to multiple of 3 4: last two digits are divisible by 4 5: ends in 5,0 6: follows the rules of both 2 and 3 9: digits add up to a multiple of 9 10: ends in 0

A prime number has no factors other than 1 and itself. Each multiple of fifteen includes 3, 5, and 15 among its factors.

I think so. Because it ends in a 3.

It would help to have that other number. If the other number is a multiple of 3, the LCM is that number. If it is not a multiple of 3, the LCM is 3 times that number.