4 is an even number and so all multiples of 4 must be even. A number ending in 3 is not even and so cannot be a multiple of 4.
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Check it out: 4,8,12,16,20,24,28,32,36. No threes.
A number that ends in 3 can't be a multiple of 4 because the 4 times table goes in a pattern, (e.g 4, 8, 12, 16, 20, 24.) If the number ends in either 0 2 4 6 8 then it couldbe a possible multiple of 4. It always ends in an even number. 3 is not an even number so it is not going to be the last number of a multiple of 4.
A number that is divisible by 6 but not by 3 must be a multiple of 6 that is not a multiple of 3. Since 6 is a multiple of 3 (6 = 2 * 3), any multiple of 6 will also be a multiple of 3. Therefore, there is no number that is divisible by 6 but not by 3.
Well, honey, let me break it down for you. To check if a number is a multiple of 3, you just need to add up the digits and see if that sum is divisible by 3. In this case, 1 + 0 + 3 = 4, which is not divisible by 3. So, no, 103 is not a multiple of 3. Next question, please!
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!