Q: Why can't you log 0?

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with something called logarithms. So 1 = (1 + x)^5 log 1 = log ((1+x)^5) log 1 = 5 x log (1 +x) but log 1 = 0 therefore 0 = 5 x log(1+x) divide both sides by 5 and you get 0 = log (1+x) we know that log 1 = 0, therefore 1+ x = 1 and so x = 0

i cant figure it out sorry

log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990

acording to me the value is 0 because the value of log 1 at any base is always 0.

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you cant log out from it you have to delete it or have it left

the definition of log N = X is 10 to the X power =N for log 0 we have 10 to the x power = 0 The solution for x is that x is very large (infinite) and negative, that is, minus infinity As N gets smaller and smaller, log N approaches minus infinity log 1 = 0 log .1 = -1 log .001 = -3 log .000001 = -6 log 0 = -infinity

Because After The Last Episode Nobody can log in but if you win you still cant log in

we cant log in because it is under technical difficulties

you cant

use the keyboard

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you cant

Here are a few, note x>0 and y>0 and a&b not = 1 * log (xy) = log(x) + log(y) * log(x/y) = log(x) - log(y) * loga(x) = logb(x)*loga(b) * logb(bn) = n * log(xa) = a*log(x) * logb(b) = 1 * logb(1) = 0

you cant log in after a virus because it is messed up and you will have to restart it

because you cant afford to play

For a legitamete reason.