You can, so the question is based on a misunderstanding.
Divide it by the divisor (the denominator).
To move the decimal you must move the decimal in the divisor all the way to the right to make it a whole number. Then in the dividend, you move that decimal to the right the same amount of spaces you did in the divisor.
Some people do that so that the divisor becomes an integer under the impression that dividing by a whole number is, in some way, easier than dividing by a decimal.
The dividend is the numerator and the divisor is the denominator. Basically, you divide the top number (numerator) by the bottom number (denominator).
When dividing by decimals, the easiest way to do this is to modify the question so that there is no longer a decimal in the divisor. Just as with equivalent fractions, if we multiply the dividend and the divisor by the same number, we do not actually change the question. For example, consider 1 divided by 0.2 (ie 1 / 0.2) Start by multiplying the dividend and the divisor by 10 to remove the decimal in the divisor. This changes the problem to 10 / 2. We can now evaluate the division to give 10/2=5. In your specific case where you want to divide by 3.14, you would times both the dividend and the divisor by 100 to remove the decimal in the divisor. For example 6.28 / 3.14 = 628 / 314 = 2
You divide the dividend by the divisor untilthe remainder is zero; orthe decimal expression begins to repeat a string; oryou have enough digits after the decimal point for the required accuracy.
That depends on what the divisor of the division sum is - without this information it's impossible to know how much of the whole the remainder of 2 represents.
divisor Dividend ÷ Divisor = Quotient
the divisor is the number you divide with the dividend
The divisor.
Well, isn't that a happy little question! To write a remainder as a decimal, you simply divide the remainder by the divisor. This will give you a decimal representation of the remaining part. Just remember, there are no mistakes, just happy little accidents in math!
No.