Because the multiples of 4 are even numbers and 3 is an odd number
it's you can run but you can't hide, and that reminds me of a FNAF song and I'm sad
just cant
For example if the number was 5, yes the first multiple would be 5.
A prime number has no factors other than 1 and itself. Each multiple of fifteen includes 3, 5, and 15 among its factors.
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
Whole numbers ending in 8 are even numbers. All even numbers except for 2 are composite numbers.
you cant
it just cant get ant better
If 135 was a prime number its only factors would be 1 and 135, but by ending in a 5 that means 5 is a factor which means it cant be a prime number, so its factors are atleast (may be more) 1,5,27,135 which makes it composite.
Uhhh.. you cant
no u cant
cant