yes
§ In comparing two whole numbers, the one with the most digits is always the greater number. § In decimals the number with the greatest number of digits is not always the greatest.
It appears that only single digit numbers work (0 thru 9)
Any prime numbers of about 66 or 67 digits will do.
No, counting numbers you can ignore or say they have an infinate number of significant digits. By counting numbers I mean things you count, or non measurements, or numbers you wouldn't round to significant digits anyway . Measurements always have significant digits.
2
9x8x7x6x5x4x3x2x1 or 9! which equals 362880 possible combinations if no digits are repeated
Digits is how many numbers you have in a number. If you have the number 4 it has one digit if you have the number 20 it has two digits and if you have the number 558 it has three digits. So basically in the number 1085 it has 4 digits because there is 4 numbers in it, the numbers are 1,0,8 and 5. Hoped you understand.
no, it matters with the number not digits
Armstrong numbers are the sum of their own digits to the power of the number of digits.
roman numbers............
In the numbers 1-9 each number has 1 digit and there are 9 of them, so that's 9.In 10-99 each number has 2 digits, and there are 90 of them: 2x90 = 180There are 900 three digit numbers [100 through 999]: 2700 digits.There are 9000 four digit numbers: 36000 digits.90,000 numbers with five digits: 450,000 digits.900,000 numbers with six digits: 5,400,000 digits.Then 1 number with seven digits: 7 digits.Add them up and you have 5,888,896 digits.
If the sum of the digits of a given number equals nine or a multiple of nine, nine is a factor of that number.