You plug the number back into the original equation. If you have a specific example, that would help.
Checking your solution in the original equation is always a good idea,simply to determine whether or not you made a mistake.If your solution doesn't make the original equation true, then it's wrong.
11k+7.7=15.4
If you don't learn to solve equations then guess and check is the only way to arrive at new information.
The rational numbers form a field. In particular, the sum or difference of two rational numbers is rational. (This is easy to check directly). Suppose now that a + b = c, with a rational and c rational. Since b = c - a, it would have to be rational too. Thus you can't ever have a rational plus an irrational equalling a rational.
There are plenty of places in order for one to learn more about algorithmic equations. However, one might want to check out brief information about algorithmic equations on the website Wikipedia.
1. First we need to determine the least common denominator of the fractions in the given rational equation. 2. We need to take out the fractions by multiplying All terms by the least common denominator. 3. Then we have to simplify the terms in rational equation. 4. Solve the resulting equation. 5. Check the answers to make confident the solution does not make the fraction undefined.
Checking your solution in the original equation is always a good idea,simply to determine whether or not you made a mistake.If your solution doesn't make the original equation true, then it's wrong.
11k+7.7=15.4
If you don't learn to solve equations then guess and check is the only way to arrive at new information.
it is already out. go check it out at radicalplay.com
Double check this problem if you typed it in right. Typically you do: x+y=390 and xy=1380 and use systems of equations. The answers will come out as complex decimals according to this problem.
The basic method is the same as for other types of equations: you need to isolate the variable ("x", or whatever variable you need to solve for). In the case of radical equations, it often helps to square both sides of the equation, to get rid of the radical. You may need to rearrange the equation before squaring. It is important to note that when you do this (square both sides), the new equation may have solutions which are NOT part of the original equation. Such solutions are known as "extraneous" solutions. Here is a simple example (without radicals): x = 5 (has one solution, namely, 5) Squaring both sides: x squared = 25 (has two solutions, namely 5, and -5). To protect against this situation, make sure you check each "solution" of the modified equation against the original equation, and reject the solutions that don't satisfy it.
The rational numbers form a field. In particular, the sum or difference of two rational numbers is rational. (This is easy to check directly). Suppose now that a + b = c, with a rational and c rational. Since b = c - a, it would have to be rational too. Thus you can't ever have a rational plus an irrational equalling a rational.
There are plenty of places in order for one to learn more about algorithmic equations. However, one might want to check out brief information about algorithmic equations on the website Wikipedia.
check your answers
1) When solving radical equations, it is often convenient to square both sides of the equation. 2) When doing this, extraneous solutions may be introduced - the new equation may have solutions that are not solutions of the original equation. Here is a simple example (without radicals): The equation x = 5 has exactly one solution (if you replace x with 5, the equation is true, for other values, it isn't). If you square both sides, you get: x2 = 25 which also has the solution x = 5. However, it also has the extraneous solution x = -5, which is not a solution to the original equation.
MIT has created this application that recognizes most written equations! Check out the link below and play around with it.