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1) When solving radical equations, it is often convenient to square both sides of the equation.
2) When doing this, extraneous solutions may be introduced - the new equation may have solutions that are not solutions of the original equation.
Here is a simple example (without radicals): The equation
x = 5
has exactly one solution (if you replace x with 5, the equation is true, for other values, it isn't). If you square both sides, you get:
x2 = 25
which also has the solution x = 5. However, it also has the extraneous solution x = -5, which is not a solution to the original equation.
What else can I help you with?
In general when solving a radical equation should you first isolate the radical and then both sides?
It often helps to isolate the radical, and then square both sides. Beware of extraneous solutions - the new equation may have solutions that are not part of the solutions of the original equation, so you definitely need to check any purported solutions with the original equation.
What are the steps to solving a radical equation?
Details may vary depending on the equation. Quite often, you have to square both sides of the equation, to get rid of the radical sign. It may be necessary to rearrange the equation before doing this, after doing this, or both. Squaring both sides of the equation may introduce "extraneous" roots (solutions), that is, solutions that are not part of the original equation, so you have to check each solution of the second equation, to see whether it is also a solution of the first equation.
How is solving radical equations similar to solving linear equations?
It really is utilized to solve specific variablesIt really is utilized to rearrange the word.
When solving a radical equation you should first isolate the radical and then?
It often helps to square both sides of the equation (or raise to some other power, such as to the power 3, if it's a cubic root).Please note that doing this may introduce additional solutions, which are not part of the original equation. When you square an equation (or raise it to some other power), you need to check whether any solutions you eventually get are also solutions of the original equation.
What property of the square root is essential in order to solve any radical equation involving a square root?
The property that is essential to solving radical equations is being able to do the opposite function to the radical and to the other side of the equation. This allows you to solve for the variable. For example, sqrt (x) = 125.11 [sqrt (x)]2 = (125.11)2 x = 15652.5121
Do Radical equations sometimes have extraneous solutions?
Yes, radical equations can sometimes have extraneous solutions. When solving these equations, squaring both sides to eliminate the radical can introduce solutions that do not satisfy the original equation. Therefore, it is essential to check all potential solutions in the original equation to verify their validity.
When do you need to check for extraneous solutions?
You need to check for extraneous solutions when solving equations containing variables in denominators or within radical expressions. These solutions may arise from introducing new roots or excluded values during manipulations, which need to be verified to ensure they are valid in the original equation.
How do you solve radical equation and identify any extraneous roots?
To solve a radical equation, isolate the radical on one side of the equation and then square both sides to eliminate the radical. After squaring, simplify the resulting equation and solve for the variable. Finally, check all potential solutions by substituting them back into the original equation to identify any extraneous roots, which are solutions that do not satisfy the original equation.
In general when solving a radical equation should you first isolate the radical and then both sides?
It often helps to isolate the radical, and then square both sides. Beware of extraneous solutions - the new equation may have solutions that are not part of the solutions of the original equation, so you definitely need to check any purported solutions with the original equation.
In general when solving a radical equation you should first the radical and then square both sides.?
In general, when solving a radical equation, you should first isolate the radical on one side of the equation. Once the radical is isolated, you can then square both sides of the equation to eliminate the radical. After squaring, it’s important to check for extraneous solutions, as squaring both sides can introduce solutions that do not satisfy the original equation.
What reasoning and explanations can be used when solving radical equations?
The basic method is the same as for other types of equations: you need to isolate the variable ("x", or whatever variable you need to solve for). In the case of radical equations, it often helps to square both sides of the equation, to get rid of the radical. You may need to rearrange the equation before squaring. It is important to note that when you do this (square both sides), the new equation may have solutions which are NOT part of the original equation. Such solutions are known as "extraneous" solutions. Here is a simple example (without radicals): x = 5 (has one solution, namely, 5) Squaring both sides: x squared = 25 (has two solutions, namely 5, and -5). To protect against this situation, make sure you check each "solution" of the modified equation against the original equation, and reject the solutions that don't satisfy it.
What happens if you are checking a solution for the radical expression and find that it makes one of the denominators in the expression equal to zero?
Then it is not a solution of the original equation. It is quite common, when solving equations involving radicals, or even when solving equations with fractions, that "extraneous" solutions are added in the converted equation - additional solutions that are not solutions of the original equation. For example, when you multiply both sides of an equation by a factor (x-1), this is valid EXCEPT for the case that x = 1. Therefore, in this example, if x = 1 is a solution of the transformed equation, it may not be a solution to the original equation.
What is a radical equation?
They are actually to the one half power. You can take a factor in the radical and sqrt it and put in on the outside... Ex. sqrt(28) = sqrt(4 * 7) = sqrt(22 * 7) = 2sqrt(7) sqrt(28) = 2 * sqrt(7)
CAn someone help me with my radical equations?
There are several good websites to find help with radical equations. You tube has several good videos on radical equations that are free of charge.
What are the steps to solving a radical equation?
Details may vary depending on the equation. Quite often, you have to square both sides of the equation, to get rid of the radical sign. It may be necessary to rearrange the equation before doing this, after doing this, or both. Squaring both sides of the equation may introduce "extraneous" roots (solutions), that is, solutions that are not part of the original equation, so you have to check each solution of the second equation, to see whether it is also a solution of the first equation.
What is the difference between a radical equation and a quadratic equation?
radical equations have sq roots, cube roots etc. Quadratic equations have x2.
Do all quadratic equations have two solutions?
I may only be in 8th grade but I am absolutely positive that all quadratic equations have 2 solutions. No - They may have 0,1, or 2 answers For example, the problem x^2 + 8x +16 = 0 has only one solution -4. This is because the radical evaluates to 0 rendering the +/- sign irrelevant.
