It doesn't; they have the same number of factors.
Factors: (will fill in later).Prime Factors: 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5
2 x 5 x 5 = 50
The factors of 5 are 1 and 5. The factors of 2 are 1 and 2.
The factors of 2 are:1, 2The factors of 5 are:1, 5
The positive integer factors of 20 are: 1 2 4 5 10 20 The positive integer factors of 30 are: 1 2 3 5 6 10 15 30 Therefore, out of the two numbers, 30 has more factors.
Do you mean, what is it evenly divisible by? You can answer questions like these by finding the factors of the number and multiplying different factors: 215 ends in 5, so we know 5 is one if its factors. Divide by 5: we're left with 43. 43 is a prime number, it can't be factored any more. 215 is only divisible by 5 and 43. As a better example of how this technique works, consider 100. 100's factors are 5, 5, 2, and 2. By multiplying together different factors, we can discover that 100 is not only divisible directly by its factors 5 and 2, but also by 5*5, 2*2, 5*2, 5*5*2 and 2*2*5.
25 factors to [5 5] 125 factors to [5 5 5] 200 factors to [2 2 2 5 5] Common factors are [5 5] so GCF = 25 25
The prime factors are: 2 x 2 x 5
The prime factors of 100 are 2 x 2 x 5 x 5, and one more x 2 gives the prime factors of 200, 2 x 2 x 2 x 5 x 5. The factors of 100 are 1, 2, 4, 5, 10, 20, 25, 50, and 100. These are also the common factors of 100 and 200, but there is no obvious way to find the factors of 200 by using common factors. The factors of 200 are 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, and 200.
5 and 9 come to mind (there are more of course)
The prime factors of 100 are 2 x 2 x 5 x 5, and one more x 2 gives the prime factors of 200, 2 x 2 x 2 x 5 x 5. The factors of 100 are 1, 2, 4, 5, 10, 20, 25, 50, and 100. These are also the common factors of 100 and 200, but there is no obvious way to find the factors of 200 by using common factors. The factors of 200 are 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, and 200.
They have the prime factors 2 and 5 in common.