In a solid state, the molecules are bound together; these bonds must be broken to convert the substance from solid to liquid, and that requires energy.
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
A BTU is the amount of energy required to raise the temperature of 1 pound of water 1 degree Fahrenheit (F) at or near 39.2 degrees F and 1 atmosphere of pressure. Electric heaters are rated in KW, not BTU's 3413 BTU's = 1 KW-hr. Check the link below for a PDF on water heater sizing.
A 100 pound propane tank has a capacity of 2,160,509 BTUs
A fourty two (42) gallon barrel of oil generates approximately 5,600,000 btus. A cubit foor of nat gas generates 1,200 btus ,there for you would need 4,666.67 cubic feet of gas or 4.6 mcf. Today, an mcf of nat gas costs $2.6 an mcf, a barrel of oil $106. The btu per dollar breakdown looks like this. 5,600,000 btus = 1 barrel of crude oil = $106 5.6m btu / $106 = 52,830 btus per dollar 5,600,000 btus = 4.66 mcf = $12.12 5.6m btus / $12.12 = 462,046 btus per dollar
Salt water cubes melt fast because the salt make it give up its BTUs faster
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
6,520 Btus
BTUs to Evaporate One Pound of WaterQuick Answer: Somewhere around 1000BTU/lb Long answer: It depends on the temperature of the water you start with. Before you can evaporate the water, you must heat it to it's boiling point. The warmer the water you start with the fewer BTUs will be needed to heat the water to its boiling point. Keep in mind the BTUs require to raise the water to its boiling point are very few compared to the BTUs required to change the water from a liquid to a gas.One pound of steam contains 1150 BTUs. This is the energy you need to put into the water for it to evaporate if you start with water at 32F. If you start with water at 100F the water already has 70 BTU/lb so the BTUs required to evaporate the water when you start at 100F is 1150-70 = 1080 BTU and so on.You can get all this information in a steam table which can be found easily by searching the web.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
1 btu raises 1 lb water 1 degree F from 62 to 63 degrees. generally 1 btu/lb/degree F x 20 degrees F difference x 15 lbs = 300 btus specifically the heat of the liquid at 100F is 67.97 btus and at 120F = 87.92 btu 87.92 - 67.97 = 19.95 btu 19.95 x 15 lbs. = 299.25 btus to be more accurate
1320 btu`s
Depends on the temperature of the water. If it is 32 degree water and you want 32 degree ice then you need a -144 BTU loss to change state from liquid to solid. It takes 1 BTU to raise the temperature of 1 pound of water 1 degree (F). If the water is 82 degrees then you would need a -50 BTU loss (+) 144 BTU to change state. TOTAL WEIGHT OF WATER (X) 1 BTU (X) Degrees desired of change. If it is ICE to WATER then it is the TEMP of ICE (X) .5 BTU (X) NUMBER OF DEGREES INCREASED = TOTAL BTU needs. If you change state in the process you have to add 144 BTU for 32 degree ICE to 32 degree WATER and 970 BTU for 212 degree WATER to 212 degree STEAM but only when you change state.
One measure does not directly translate to another. A BTU is the amount of heat that it takes to raise the temp of one pound of water by one degree F. A burning match, and a burning fireplace may both be at 650 degrees, but the fireplace gives off more heat (more BTUs)