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The period of the pendulum is (somewhat) inversely proportional to the square root of the length. Therefore, the frequency, the inverse of the period, is (somewhat) proportional to the square root of the length.
time period of simple pendulum is dirctly proportional to sqare root of length...
the time period of a pendulum is proportional to the square root of length.if the length of the pendulum is increased the time period of the pendulum also gets increased. we know the formula for the time period , from there we can prove that the time period of a pendulum is directly proportional to the effective length of the pendulum. T=2 pi (l\g)^1\2 or, T isproportionalto (l/g)^1/2 or, T is proportional to square root of the effective length.
The period is proportional to the square root of the length so if you quadruple the length, the period will double.
Since the period of a simple pendulum (for short swings) in proportional to the square root of its length, then making the length one quarter of its original length would make the period one half of its original period.Periodapproximately = 2 pi square root (length/acceleration due to gravity)
The period is directly proportional to the square root of the length.
The period of the pendulum is (somewhat) inversely proportional to the square root of the length. Therefore, the frequency, the inverse of the period, is (somewhat) proportional to the square root of the length.
The period increases as the square root of the length.
time period of simple pendulum is dirctly proportional to sqare root of length...
Yes, the length of pendulum affects the period. For small swings, the period is approximately 2 pi square-root (L/g), so the period is proportional to the square root of the length. For larger swings, the period increases exponentially as a factor of the swing, but the basic term is the same so, yes, length affects period.
the time period of a pendulum is proportional to the square root of length.if the length of the pendulum is increased the time period of the pendulum also gets increased. we know the formula for the time period , from there we can prove that the time period of a pendulum is directly proportional to the effective length of the pendulum. T=2 pi (l\g)^1\2 or, T isproportionalto (l/g)^1/2 or, T is proportional to square root of the effective length.
The period is proportional to the square root of the length so if you quadruple the length, the period will double.
Measure the period, the period is directly proportional to the square root of the length.
Since the period of a simple pendulum (for short swings) in proportional to the square root of its length, then making the length one quarter of its original length would make the period one half of its original period.Periodapproximately = 2 pi square root (length/acceleration due to gravity)
The time period is directly proportional to the square root of length of the pendulum and inversely proportional to the square root of acceleration due to gravity.
the period of the pendulum increases with the square root of the length so if the length is four times, the period just doubles.
The frequency of a pendulum is inversely proportional to the square root of its length.