Because they are all factors of 256
256 is divisible by 2, 4, and 8.
1, 2, 4, 8, 16, 32, 64, 128, 256.
256/2 = 128, 128/2 = 64, 64/2 = 32, 32/2 = 16, 16/2 =8, 8/2 = 4, 4/2 = 2, 2/2 = 1, and therefore 256/28 = 1 All even numbers are divisible by 2.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.
Yes. 8 / 4 = 2 8 is also divisible by 2 and 8.
4 is divisible by 1, 2 and 4. So is 8. If a number is divisible by 8, it will also be divisible by 4.
are 2 and 8 divisible by 4
2 times 4 equals 8. 8 is divisible by 2 and 4, but 2 and 4 are NOT divisible by 8. 8 is a multiple of 2 and 4. If you want to be technical, any number (other than zero) is divisible by any number. I assume you mean divisible evenly, in which case the above answer will answer your question.
Yes. To check if a number is divisible by 2, the last digit must be divisible by 2, ie one of {0. 2. 4. 6. 8} (the even digits). 712 ends in 2 which is an even digit, so 712 is divisible by 2 (and thus even).
4^4=4*4*4*4 = 256 OR (2^2)^4 = 2^8 = 256
Being divisible by 4, means that it will also be divisible by 2, so that doesn't tell you anything about divisibility by 8. But if you divide the number by 2, and this quotient is divisible by 4, then yes the original number is divisible by 8.
8, 16, 24, 32... All multiples of 8 are also divisible by 2 and 4.