I am not at all convinced that it is. With more than three variables it is almost impossible and even with 3 variables, it is hard going.
Linear programming is just graphing a bunch of linear inequalities. Remember that when you graph inequalities, you need to shade the "good" region - pick a point that is not on the line, put it in the inequality, and the it the point makes the inequality true (like 0
Just saying "no solution" is good enough
Hi, my daughter's math teacher recommended a website to his students. It has a lot of math video lessons on various math topics, including the one you need help with. Please click the below link 'Free absolute value inequalities video'. It is all FREE to use! It was very helpful for my child. Hope it will help you, too. Good luck!
no because punishment is not a solution for the fault. Good and polite language is good punishment; aunt of matilda is bad as she left her child alone
Get all the terms on one side of the equation, leaving the other side zero.If the highest exponent is 2, the quadratic formula will suffice.If the highest exponent is 3, the cubic formulas will suffice.The quadratic and cubic formulas can be found athttp://www.math.vanderbilt.edu/~schectex/courses/cubic/If the highest exponent is 4, the quartic formulas will suffice. These are found at http://planetmath.org/encyclopedia/QuarticFormula.html(Good Luck!)If the highest exponent is greater than 4, there is no procedure for solving the equation, BUT because all polynomials are continuous, it is possible to find a number closer to a solution than any number selected (if there is a real solution). Therefore, an approximation of real solutions is possible.For example: 2X^7-3X^4+X^3-1.5X+14=0let 2x^7-3x^4+x^3-1.5x+14=ylet x=0 ... y=14 (positive; now we need a negative output)let x=-2 ... y=-295 (so a solution X lies between -2 & 0)let x=-1 ... y=9.5 POSITIVE (-2
tty
In question and answer logic answers are given and if they fall in an area bounded by the inequality then it is a good answer. After graphing three or more inequalities the vertexes are the possible maxima of the system of equations.
Linear programming is just graphing a bunch of linear inequalities. Remember that when you graph inequalities, you need to shade the "good" region - pick a point that is not on the line, put it in the inequality, and the it the point makes the inequality true (like 0
1) Replace the inequality signs in the solution and in the original question with = signs. Substitute the solution inn the question: it should make it true. 2) (Back to the inequalities) Pick another number that satisfies the solution inequality - e.g. if x>2, pick 5. Substitute this into the original inequality: if it makes it true, then you are good to go!
Just saying "no solution" is good enough
no
Texas Instruments TI-84 Plus Graphing Calculator is a reasonably priced, good graphing calculator.
Graphing is not necessarily easier than elimination or substitution. If you are good at drawing graphs, and do not like algebra, then graphing is easier. However, elimination and substitution are much faster, and graphing can often get awkward when working with more complicated formulae.
Yes you can buy a graphing calculator. I know they are sold at places like Walmart, and Target and most of them are around $100 but go on sale before school starts for around $90. TI-83 and TI-84 graphing calculators are really good.
what is the solution for a good nutrition
The Casio FX-9750GPlus Graphing Calculator is good.
The Texas Instruments TEXTI84PLUSSE Graphing Calculator is good for calculus too.