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Why is it not possible for the graph of a rational function to cross its vertical asymptotes?
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How many non-verticle asymptotes can a rational function have?
Not sure what non-verticle means, but a rational function can have up to 2 non-vertical asymptotes,
Can a rational function have no vertical horizontal oblique asymptotes?
No, it will always have one.
How many vertical asymptotes can there be in a rational function?
Factoring is usually helpful in identifying zeros of denominators. If there are not common factors in the numerator and the denominator, the lines x equal the zeros of the denominator are the vertical asymptotes for the graph of the rational function. Example: f(x) = x/(x^2 - 1) f(x) = x/[(x + 1)(x - 1)] x + 1 = 0 or x - 1 = 0 x = -1 or x = 1 Thus, the lines x = -1 and x = 1 are the vertical asymptotes of f.
A function has vertical asymptotes at x-values for which it is and near which the function's values become very positive or negative numbers?
Undefined; large
What are the slopes of the hyperbola's asymptotes?
If a hyperbola is vertical, the asymptotes have a slope of m = +- a/b. If a hyperbola is horizontal, the asymptotes have a slope of m = +- b/a.
How many non-verticle asymptotes can a rational function have?
Not sure what non-verticle means, but a rational function can have up to 2 non-vertical asymptotes,
Can a rational function have no vertical horizontal oblique asymptotes?
No, it will always have one.
Can the graph of a rational function have more than one vertical asymptote?
Assume the rational function is in its simplest form (if not, simplify it). If the denominator is a quadratic or of a higher power then it can have more than one roots and each one of these roots will result in a vertical asymptote. So, the graph of a rational function will have as many vertical asymptotes as there are distinct roots in its denominator.
How many vertical asymptotes does the graph of this function have?
2
The vertical of the function secant are determined by the points that are not in the domain?
Asymptotes
How many vertical asymptotes can there be in a rational function?
Factoring is usually helpful in identifying zeros of denominators. If there are not common factors in the numerator and the denominator, the lines x equal the zeros of the denominator are the vertical asymptotes for the graph of the rational function. Example: f(x) = x/(x^2 - 1) f(x) = x/[(x + 1)(x - 1)] x + 1 = 0 or x - 1 = 0 x = -1 or x = 1 Thus, the lines x = -1 and x = 1 are the vertical asymptotes of f.
A sign chart helps you record data about a function's values around its and asymptotes?
A sign chart helps you record data about a function's values around its _____ and _____ asymptotes. zeros vertical
A function has vertical asymptotes at x-values for which it is and near which the function's values become very positive or negative numbers?
Undefined; large
The vertical of the function cosecant are determined by the points that are not in the domain?
The answer depends on what you mean by "vertical of the function cosecant". cosec(90) = 1/sin(90) = 1/1 = 1, which is on the graph.
How do you find horizontal and vertical asymptotes?
finding vertical asymptotes is easy. lets use the equation y = (2x-2)/((x^2)-2x-3) since its a rational equation, all we have to do to find the vertical asymptotes is find the values at which the denominator would be equal to 0. since this makes it an undefined equation, that is where the asymptotes are. for this equation, -1 and 3 are the answers for the vertical ayspmtotes. the horizontal asymptotes are a lot more tricky. to solve them, simplify the equation if it is in factored form, then divide all terms both in the numerator and denominator with the term with the highest degree. so the horizontal asymptote of this equation is 0.
What are the three types of asymptotes?
Three types of asymptotes are oblique/slant, horizontal, and vertical
What are the slopes of the hyperbola's asymptotes?
If a hyperbola is vertical, the asymptotes have a slope of m = +- a/b. If a hyperbola is horizontal, the asymptotes have a slope of m = +- b/a.
