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This is because of the rule for calculating total resistance of parallel resistors. 1/Rtotal = 1/R1 + 1/R2 + 1/R3 + ....

Let us take two resistors in parallel. R1 = 100 ohms and R2 = 330 ohms.

From the general formula above we can calculate our total resistance as follows:

1/Rtotal = 1/R1 + 1/R2

1/Rtotal = 1/100 + 1/330

multiply 1/ R1 by 3.3/3.3

1/Rtotal = 3.3/330 + 1/330

1/Rtotal = 4.3/330

invert both sides

Rtotal = 330/4.3

Rtotal = 76.744.....ohms

Now let's consider a much closer example, R1 = 100 ohms and R2 = 110 ohms.

From the general formula above we can calculate our total resistance as follows:

1/Rtotal = 1/R1 + 1/R2

1/Rtotal = 1/100 + 1/110

multiply 1/ R1 by 1.1/1.1

1/Rtotal = 1.1/110 + 1/110

1/Rtotal = 2.1/110

invert both sides

Rtotal = 110/2.1

Rtotal = 52.38.....ohms

Q: Why is it that the total resistance is less than the smallest resistive value?

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