This is because of the rule for calculating total resistance of parallel resistors. 1/Rtotal = 1/R1 + 1/R2 + 1/R3 + ....
Let us take two resistors in parallel. R1 = 100 ohms and R2 = 330 ohms.
From the general formula above we can calculate our total resistance as follows:
1/Rtotal = 1/R1 + 1/R2
1/Rtotal = 1/100 + 1/330
multiply 1/ R1 by 3.3/3.3
1/Rtotal = 3.3/330 + 1/330
1/Rtotal = 4.3/330
invert both sides
Rtotal = 330/4.3
Rtotal = 76.744.....ohms
Now let's consider a much closer example, R1 = 100 ohms and R2 = 110 ohms.
From the general formula above we can calculate our total resistance as follows:
1/Rtotal = 1/R1 + 1/R2
1/Rtotal = 1/100 + 1/110
multiply 1/ R1 by 1.1/1.1
1/Rtotal = 1.1/110 + 1/110
1/Rtotal = 2.1/110
invert both sides
Rtotal = 110/2.1
Rtotal = 52.38.....ohms
Chat with our AI personalities
The smallest value is 0.
It means the smallest value.
The smallest value is 5.
It is a passive electrical device with a resistive value of 1000 ohms, used for limiting current or dropping voltage.
The range is the size of the set of data. Take the smallest from the largest value to get the range
the filament is made of tunguston which is having high resistance value,Hence it's resistive load
i think it is high value resistance as it is used in Transformers to get the output voltage.
In a parallel circuit, the total resistance is the inverse of the total of 1 over the value of the first resistor plus 1 over the value of the second resistor. Said another way, if you take 1 over the value of R1 plus 1 over the value of R2, and then take 1 over that, you will find Rtotal. So let's do that. 1/10 + 1/2 = 1/10 + 5/10 = 6/10 1 divided by 6/10 = 10/6 = 1 2/3 ohms for the total resistance. As a quick check, in any parallel network where a group of resistive elements are all connected in parallel, the total resistance will be less than the value of the smallest one. The smallest one in this case is 2 ohms, so we are good to go by that simple check.
If the wires are of identical materials, the 26 guage wire has more (higher) resistance.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
Resistance of the load = voltage across the load/current through the loadWhich means that the resistance would be 3 ohms.(This is only true assuming that the load is purely resistive and the ammeter is ideal.)
what is the value of the smallest division on a ammeter
Resistive Load An electrical load which is characteristic of not having any significant inrush current. When a resistive load is energised, the current rises instantly to it's steady-state value, without first rising to a higher value. An electrical load in which voltage and current are converted to energy in the form of heat; i.e., an electrical heater, incandescent bulb. Inductive Load An electrical load which pulls a large amount of current (an inrush current) when first energized. After a few cycles or seconds the current "settles down" to the full-load running current. The time required for the curren to "settle down" depends on the frequency or/and the inductance value of the Inductive load
what is the value of the smallest division on a ammeter
Resistances in series act just as if they were one single resistor. The value of the single resistor is the sum of the individual resistors connected in series ... Ra + Rb + Rc etc. When several resistors are in series, the effective total is greater than the biggest one. Resistance in parallel act just as if they were one single resistor. The reciprocal of the value of the single resistor is the sum of the reciprocals of the individual resistors connected in parallel ... Total effective resistance = 1 divided by (1/Ra + 1/Rb + 1/Rc + etc.) When several resistors are in parallel, the effective total is less than the smallest one. Once you figure out the effective value of the series- or parallel-combination of many resistors, you handle them as if they were one single resistor, and you can work with the voltage and current: Current through any resistance = (Voltage across it) divided by (its resistance).
The number of ohms is, precisely, the value of the resistance.
what is the diference betwean calculated and maesured value