in water there are two bond pairs and two lone pairs where as in CH4 there are are four bond pairs nad no lone pair.
in ch4 there is only bond pair to bond pair repulsion but in water there are three types of repulsions, lone to lone (greatest repulsion), lone to bond ( lesser repulsion ) and bond to bond ( the least repulsion) , therefore due to the presence of two lone pairs in water the bond pairs are repelled with greater force and they get compressed, reducing the ideal bond angle from 109.5 to 104.5
on the other hand, ch4 has only bond pairs and they dont repel each other that strongly so its angle is greater n its 109.5..
No, the bond angle for linear structure is 180 degrees.
ClO3 has the smaller bond angle than ClO4
Yes, water is a bend molecule with a bond angle of about 105 degrees. They are described as bent planar (or V shaped)
bond angle
The molecular geometry and bond angle of clone is the result of a tetrahedral electron. It is common to be called a bent molecule.
The water molecule's bond angle is about 104.45 degrees.
The lone pair - OH bond repulsion in water is greater than the OH bond- OH bond repulsion. In methane all of the bonds are the same so it has perfect tetrahedral symmetry. This is VSEPR theory
If the question is "What is the likely bond angle for selenium hydride," then the answer is 105 degrees, just like a water molecule.
104.5 degrees
Increases
Bond angle is 109.5 degrees.It is equal in every bond
The bond angle of the H-O-H is equivalent to 105 degrees.
NH4+ is tetrahedral, with bond angle of 109.5o
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
Bond Angle (:
The bond angle for H2S is 92.1­°.
there is repulsion between lone pair and bond pair for example in water molecule oxygen has lone pair which repells the bond pair due to this bond angle decreases simply ddue to repulsion btween lone pair to lone pair or lone pair to bond pair angle varies