The lone pair - OH bond repulsion in water is greater than the OH bond- OH bond repulsion. In methane all of the bonds are the same so it has perfect tetrahedral symmetry. This is VSEPR theory
The water molecule's bond angle is about 104.45 degrees.
The bond angle of a CO2 molecule is 180 degrees.
The bond angle in water (H₂O) is less than that in methane (CH₄) primarily due to the presence of lone pairs of electrons in water. Water has a bent molecular shape with a bond angle of approximately 104.5 degrees, influenced by two lone pairs on the oxygen atom that repel the hydrogen atoms more strongly. In contrast, methane has a tetrahedral shape with a bond angle of about 109.5 degrees, where there are no lone pairs, allowing for a more symmetrical distribution of electron density around the central carbon atom.
The bond angle of a CH3F molecule is approximately 109.5 degrees.
The bond angle of the molecule CH3Cl is approximately 109.5 degrees.
The bond angle of the molecule SCl2 is approximately 103 degrees.
The ideal bond angle for a carbon-hydrogen bond in a molecule is approximately 109.5 degrees.
In a methane (CH4) molecule, the angle between each of the covalent bonds (C-H bonds) is approximately 109.5 degrees. This angle is due to the tetrahedral molecular geometry of methane, where the carbon atom is at the center of a tetrahedron with each hydrogen atom at a corner.
The angle between the bonds of a water molecule is approximately 104.5 degrees. This angle is due to the molecular geometry of water, which is bent or V-shaped.
Hydrogen the molecule doesn't have a bond angle. You have to have an atom with at least two other atoms bonded to it to have a bond angle, and hydrogen has only two atoms total.
The bond angle of the SO2 molecule is approximately 120 degrees, and its shape is bent or angular.
The bond angle in a molecule containing a CH3Br group is approximately 109.5 degrees.