The lone pair - OH bond repulsion in water is greater than the OH bond- OH bond repulsion. In methane all of the bonds are the same so it has perfect tetrahedral symmetry. This is VSEPR theory
The molecular geometry is square planar and the bond angle is 90 degrees
180
180 degree
90
The bond angle between the two hydrogen is 104.5 degrees. If it weren't for the two unshared pairs of electrons pushing those atoms into a v-shape, the molecule would be linear.
The water molecule's bond angle is about 104.45 degrees.
The bond angle in the linear molecule is 180 degrees.
If the question is "What is the likely bond angle for selenium hydride," then the answer is 105 degrees, just like a water molecule.
Methane is a molecule with covalent bonds. Then again, there are different types of bonds. To be specific, Methane is a tetrahedral molecule with covalent long single bonds.
The bond angle of the H-O-H is equivalent to 105 degrees.
the water molecule is bent because of the two pairs of electrons around the oxygen.
Yes, water is a bend molecule with a bond angle of about 105 degrees. They are described as bent planar (or V shaped)
The question is nonsense. WHICH bond angle? There are many of them in a molecule the size of estradiol.
round about 109.5
A tetrahedral molecule will have a 109.5 degree bond angle.
180 degrees as it is linear
Hydrogen the molecule doesn't have a bond angle. You have to have an atom with at least two other atoms bonded to it to have a bond angle, and hydrogen has only two atoms total.