The lone pair - OH bond repulsion in water is greater than the OH bond- OH bond repulsion. In methane all of the bonds are the same so it has perfect tetrahedral symmetry. This is VSEPR theory
The water molecule's bond angle is about 104.45 degrees.
The bond angle of a CO2 molecule is 180 degrees.
The bond angle of a CH3F molecule is approximately 109.5 degrees.
The bond angle of the molecule CH3Cl is approximately 109.5 degrees.
The bond angle of the molecule SCl2 is approximately 103 degrees.
The ideal bond angle for a carbon-hydrogen bond in a molecule is approximately 109.5 degrees.
In a methane (CH4) molecule, the angle between each of the covalent bonds (C-H bonds) is approximately 109.5 degrees. This angle is due to the tetrahedral molecular geometry of methane, where the carbon atom is at the center of a tetrahedron with each hydrogen atom at a corner.
The bond angle of the SO2 molecule is approximately 120 degrees, and its shape is bent or angular.
The bond angle in a molecule containing a CH3Br group is approximately 109.5 degrees.
Hydrogen the molecule doesn't have a bond angle. You have to have an atom with at least two other atoms bonded to it to have a bond angle, and hydrogen has only two atoms total.
The angle between the bonds of a water molecule is approximately 104.5 degrees. This angle is due to the molecular geometry of water, which is bent or V-shaped.
Yes, water is a bend molecule with a bond angle of about 105 degrees. They are described as bent planar (or V shaped)