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Q: Why is there a k for constant instead of c?
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How do you use constant K?

In chemistry, K is 273+Degrees C.


A varies directly as b and inversely as c?

A = k (b/c)'k' is some constant number.


Why do we use k for constant of proportionality?

You can basically use any letter for a constant. "c" is often used because it's the first letter of "constant"; the use of "k" probably arises either from the fact that it has the same sound, in English, as "k"; or from other languages where the word "constant" is written with a "k" (e.g., "Konstante" in German).


Why is meerkat spelled with a k instead of a c'?

Kuz they kan


What is a constant K formula?

K = constant


Why is 'meerkat' spelled with a 'k' instead of a 'c'?

Kuz they kan


What is the antiderivative squared 0 9X18 squared X 17 X 18?

Let k = 0 9x18 squared x 17 x 18 k is a constant. Its anti-derivative is kx + C, where C is a constant. The anti-derivative squared is (kx+ C) squared.


Translate C varies jointly a d and the cube of e and inversely as the square root of m?

C = k*a*d*e^3/sqrt(m) where k is a constant.


What is a pointless letter?

C, which has either an S or a K sound when it is used in words. So there is no need for a C when an S or a K could be used instead.


What is the integral of 1 over c to the power of 1 minus x?

use this strategy: integral of (b^x) dx = (b^x)/ln(b) + K [K is integration constant, b is not a variable]rewrite (1/c)^(1-x) = ((1/c)^1)*((1/c)^(-x)) = (1/c)*(c^x). (1/c) is a constant, so bring outside the integral, then let b = c in the formula above, and you have (1/c)*(c^x)/ln(c) + K


What is inversely and directly proportional?

Two variables, X and Y are said to be in inversely proportional is X*Y - k where k is some non-zero constant. X and Y are said to be directly proportional if X = c*Y where c is some constant.


Exactly 5.00 L of air at -50.0 C is warmed to 100.0 C What is the new volume if the pressure remains constant?

Vol = k*Temp where k is a constant. Vol2 = Vol1*T2/T1 = 5.00*373/223 = 8.36 litres, approx.