Who could improve on the fore going response.
However
If Isaac newton was around he would argue that the force ,which exists between any 2 objects that have mass, changes with respect to the distance between these 2 objects i.e increases the closer they are together -reduces the further they are apart.
The specific force that has the designation 'g' refers to the force between the planet Earth and objects that reside on it.
This force weakens the further that an object moves further away from the surface of the Earth and also weakens as you move from the surface to the centre of the Earth. At that point g is zero.
However modern thinkers dismiss Newton's ideas
At least I can understand Newton
I'm buggered when I try to understand the new thinkers.
On Earth:Do you mean acceleration due to gravity?Here is your answer minimum value of g=9.8m/s2maximum value =10m/s2 approximately.Elsewhere:Anything positive and finite is theoretically possible.
It's the same as that of Earth but the value of g varies from one object to the other. The value of the gravitational constant or the BIG "G" remains constant. I think you confused it with the LITTLE "g" which is the gravitation of a object (one with mass) or the acceleration due to gravity. The value of g on Earth and Moon is 9.8m/s^2 and 1.6249m/s^2, respectively. I hope this answers you all.
9.8 is the value for g, which stands for Gravity.
TIme period T is given by the expression 2pi./l/g So T is inversely related to the g value at the place At Muree value of aceeleration due to gravity g is less than that at Karachi. Hence the result
9.8 m/s2 ---------------------- Yes this is the average value of acceleration due to gravity near by the surface of the earth. As we go higher and higher level this g value decreases and becomes almost negligible. Same way as we go deeper and deeper the g value decreases and at the centre of the earth its value becomes zero.
As soon as you go below the surface, it will decrease (dont ask for the calculations) until at its centre where acceleration due to gravity will be 0.
the pressure of liquid is HDG where H=depth D=density g= acceleration due to gravity thus depth= pressure/density*acceleration due to gravity
The Pressure and depth of a liquid are related by the equation P= dgh., where d is the density, g is the acceleration due to gravity and h is the depth. This value gives us the gauge pressure that is the excess above the atmospheric pressure.This is explainable with Archimedes principal giving the pressure at the base of the column with the formula Sg x H x G
value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
The weight is due to the force exerted on the body by the gravitational pull by the earth. If no such gravitational pull on the body, then the body becomes weightless. In free space, very far away from the earth the astronauts experience weightlessness. So if M is the mass of the body, then Mg is the weight of the body. Hence weight depends on the value of 'g'. The value of g is the least at the equatorial region. It will be maximum at the poles. As we go at higher altitudes g value decreases. Same way as we go towards the centre of the earth ie as depth increases, g value decreases.
Pressure = h d g h is the depth, d the density of the liquid and g- acceleration due to gravity. As d and g remain constant, same h would have the same pressure. Hence the case.
as we go far from earths surface the value of g decreases this is because g is inversely proportional to the value of r^2(which is the distance of the body from the center of the earth.
G i.e force per unit mass on the earth surface......YES.because all calculation is approximately 10
g the acceleration due to gravity is 9.832 metres per second2 at the poles.
I hope you are talking about g which means the acceleration due to gravity.Its value is 9.8m/s2 and it vary from region to region.
I suppose you are asking about what forces change when acceleration due to gravity changes. In this case, the formula for forces concerning acceleration due to gravity is as such: fg=mg. When acceleration due to gravity(g) changes, it affects the force of gravity which is also known as the weight of the object. This is shown as fg.
g will increase when rotation is stopped because:- g depend on following thing;:- first on shape of earth second on rotation....(only Equator) not pole third one on going altitude and depth,...........