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Q: Why use exponents to express numerical values?
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What do you use decimals for?

Represent numerical values.


What is the definition of numerical analysis?

It is the study of algorithms that use numerical values for the problems of continuous mathematics.


Why everything to the power of zero is equal to 1?

This is easiest to explain with an example. One of the laws of exponents says that division of numbers containing exponents makes the exponents subtract from each other. For example, 24/23 = 2(4-3) = 21 = 2. Expanded to use numerical values, 16/8 = 2. Similarly, 23/23 = 2(3-3) = 20 = 1. It therefore follows that anything to the power zero is equal to one.


How do you express the numbers of a particular prime number using exponents?

Exponents are used to replace repeated factors. Prime numbers won't use exponents because they don't have repeated factors. To express the prime factorization of a particular composite number using exponents, just count. 2 x 2 x 2 x 3 x 3 = 72 23 x 32 = 72


How do we properly use the abbreviation ''km'' or ''kms'' with numerical statements to express road length?

Km is the appropriate one.


Use exponents to express 7560 as a product of prime factors?

23 x 33 x 5 x 7 = 7,560


Why is semi log graph paper used?

b/c of big values which are in the form of exponents and powers,we use semilog graph.....


You can approximate e by substituting large values for n into the expression Use the caret to enter exponents?

(1+1/n)^n


Express the polynomial below as a product of its factors Use the caret to enter exponents 20x3 - 15x2?

20x3-15x2=8,000-225=7,775


How do you use exponents to express 7560 as a product of prime factor?

2^3 x 3^3 x 5 x 7


How do you use order or operations to solve numerical expressions?

Order of operation: 1 - Parenthesis and brackets ( ) { } 2 - Exponents and roots n3 √n 3 - Multiplication and division X ÷ 4 - Addition and subtraction + -


Calculate the resolving power if the wavelength is 600 nm and the numerical apertures are 0 0.2 0.4 0.6 0.8 and 1.0?

Use the Equation, Resolving Power=lambda/2(Numerical Aperture). So, given the values for Numerical Aperture(NA): If NA=0, then R=0, NA=0.2, then R=1500, NA=0.4, then R=750, etc. Simply solve the equation substituting the provided Numerical Aperture (NA) values in.