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What is 250000 in expanded notation using powers of ten?
In expanded notation using powers of ten, 250,000 can be expressed as (2 \times 10^5 + 5 \times 10^4 + 0 \times 10^3 + 0 \times 10^2 + 0 \times 10^1 + 0 \times 10^0). Simplifying this, it becomes (2 \times 100,000 + 5 \times 10,000). Thus, the expanded form is (200,000 + 50,000).
How do you write 100102200 in expanded form?
To write the number 100102200 in expanded form, you break it down according to the value of each digit. It can be expressed as: (1 \times 10^8 + 0 \times 10^7 + 0 \times 10^6 + 1 \times 10^5 + 0 \times 10^4 + 2 \times 10^3 + 2 \times 10^2 + 0 \times 10^1 + 0 \times 10^0). Simplifying this, it becomes (100000000 + 0 + 0 + 100000 + 0 + 2000 + 200 + 0 + 0), which equals (100000000 + 100000 + 2000 + 200).
How would you write the number 37 in binary?
100101 1 times 2^0 = 1 PLUS 0 times 2^1 = 0 PLUS 1 times 2^2 = 4 PLUS 0 times 2^3 = 0 PLUS 0 times 2^4 = 0 PLUS 1 times 2^5 = 32 EQUALS 37
How do you solve 15x(7-7) (5x2)?
To solve the expression (15x(7-7)(5 \times 2)), first simplify the term inside the parentheses: (7 - 7 = 0). This means the entire expression becomes (15x \times 0 \times (5 \times 2)). Since any number multiplied by zero is zero, the final result is (0).
How do you make 800000 4000 60 2 into standard form?
To express the numbers 800,000, 4,000, 60, and 2 in standard form, you convert each number into the format ( a \times 10^n ), where ( 1 \leq a < 10 ) and ( n ) is an integer. Thus, 800,000 becomes ( 8.0 \times 10^5 ), 4,000 becomes ( 4.0 \times 10^3 ), 60 becomes ( 6.0 \times 10^1 ), and 2 is written as ( 2.0 \times 10^0 ).
What numeric value in base 10 does the binary number 10000001 represent?
The binary number 10000001 represents the value of 129 in base 10. This is calculated by taking each digit of the binary number, multiplying it by 2 raised to the power of its position (from right to left, starting at 0). Specifically, (1 \times 2^7 + 0 \times 2^6 + 0 \times 2^5 + 0 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 128 + 1 = 129).
0 times 2?
0
How do i figure out what number is equivalent to 110101001?
To find the equivalent decimal number for the binary number 110101001, you can use the positional value method. Each digit represents a power of 2, starting from the rightmost digit, which is 2^0. In this case, you calculate: (1 \times 2^8 + 1 \times 2^7 + 0 \times 2^6 + 1 \times 2^5 + 0 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0), which equals 256 + 128 + 0 + 32 + 0 + 8 + 0 + 0 + 1 = 421. Thus, 110101001 in binary is equivalent to 421 in decimal.
How many times does 4 go into 7?
1.75 times
How 101010 can be made to 950?
To convert the binary number 101010 to decimal, you can calculate its value by evaluating each bit from right to left, where each bit represents a power of 2: (1 \times 2^5 + 0 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0). This results in (32 + 0 + 8 + 0 + 2 + 0 = 42). To reach 950 from 42, you would need to add 908.
What is the binary codes decimal equivalent of 0111 0011?
The binary code 0111 0011 can be converted to its decimal equivalent by calculating the value of each bit. Starting from the right, the values are 2^0, 2^1, 2^2, and so on. This gives us: (0 \times 2^7 + 1 \times 2^6 + 1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0 = 0 + 64 + 32 + 16 + 0 + 0 + 2 + 1), which equals 115. Thus, the decimal equivalent of 0111 0011 is 115.
What times something that becomes 9?
I assume that you mean integers: 3 times 3 equals 9, as does 9 times 1. Also -3 times -3 and -9 times -1.
