To solve the expression (15x(7-7)(5 \times 2)), first simplify the term inside the parentheses: (7 - 7 = 0). This means the entire expression becomes (15x \times 0 \times (5 \times 2)). Since any number multiplied by zero is zero, the final result is (0).
5x2-8x-4
its 10
5x2 = 3 then x2 = 3/5 so that x = sqrt(3/5) = ± 0.7746
1) 5x2-55=90 +55 +55 2) 10x=145 /10 /10 x=14.5
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
5x2-8x-4
x2 • (5x2 + x + 8)
its 10
3x4-7x3+5x2-3x+6
5x2 = 3 then x2 = 3/5 so that x = sqrt(3/5) = ± 0.7746
6 + 10 = 16
1) 5x2-55=90 +55 +55 2) 10x=145 /10 /10 x=14.5
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
The question contains an algebraic expression but, since there is no equality sign, there is no equation to solve.
5x2=10
-5x2 = -75 x2 = 25 x = ±sqrt( 25 ) x = ±___
X= (3/5 , -2)