No. As the sequence increases by 5 per term, the last digit repeats as "2" "7" "2" "7" etc. Clearly, "0" is never the last digit of any of those terms, and therefore, 200 will not be in the sequence.
5
tn=5n-3
It is 5n+2 and so the next number is 22
The nth term is 5n-3 and so the next term will be 22
17 + 5 = 22 17 - 5 = 12
-22
21
12 .5
17+5=22 17-5= 12
The sequence defined by the expression (27 - 5n) is an arithmetic sequence where (n) is a non-negative integer (0, 1, 2, ...). The first few terms of the sequence can be calculated by substituting values for (n): for (n = 0), the term is 27; for (n = 1), the term is 22; for (n = 2), the term is 17, and so on. The general term decreases by 5 for each increment of (n), resulting in the sequence: 27, 22, 17, 12, 7, 2, -3, ... .
12 and 17/22
-12