Yes. It has no intercepts.
A line segment that is bent to form part of a circle would be considered an arc.
No because a line can be a vertical line so say you have the equation x=5. Then a vertical line would pass through the x intercept 5 and be vertical thus not having a y intercept. All horizontal lines have a y intercept
-3
Yes, but only of the line is vertical. (It would then be written as x = a, where a is a constant. For example, the line x = 8 does not have a y-intercept. All lines in the form y = mx+b will have a y-intercept.)
A line with a y-intercept but no x-intercept will be a straight line parallel to the x axis. It will have a slope of zero.
A line segment that is bent to form part of a circle would be considered an arc.
No because a line can be a vertical line so say you have the equation x=5. Then a vertical line would pass through the x intercept 5 and be vertical thus not having a y intercept. All horizontal lines have a y intercept
A line will have no x-intercept if it is parallel to the x-axis, otherwise it will meet up with it eventually. That would be the graph of a Y=something line.
-3
The y intercept would be 3.
Yes, but only of the line is vertical. (It would then be written as x = a, where a is a constant. For example, the line x = 8 does not have a y-intercept. All lines in the form y = mx+b will have a y-intercept.)
A line with a y-intercept but no x-intercept will be a straight line parallel to the x axis. It will have a slope of zero.
The y- intercept of a line is where the line crosses the y axis. The x- intercept is where the line crosses the x axis.
y = {slope}x + {y intercept}
If the y intercept is -6 then the equation is: y = -7x-6
The y-intercept is where the line crosses the y-axis, and the x-intercept is where the line cross the x-axis
The slope intercept equation of a line is y=mx+b, where m is the slope of the line and b is the y-intercept.